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3 years ago

(2m+7)-(3-4m) Please explain how to solve.

Mathematics

2 answers:

gayaneshka [121]3 years ago

6 0

Answer:

$2(3m+2)$

Step-by-step explanation:

The first step is to solve the parenthesis:

$(2m+7)-(3-4m) \\=2m+7-3+4m$

Now we put together similar terms:

$2m+4m+7-3=6m+4$

We have $6m+4$ and since the coefficients $6$ and $4$ are multiples of 2, We can factor a 2 from the equation, wich will give us the following:

$6m+4=2(3m+2)$

The answer is $2(3m+2)$

dybincka [34]3 years ago

5 0

1. simplify 2m+7-3+4m

2. gather like terms (2m+4m)+7-3

3. simplify 6m+7-3

4. simplify 6m+4

answer is 6m+4

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3 years ago

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3 years ago

What is the solution to 2x -8 = 2(x - 4 ) ? ALSO, explain how you solved it.

Genrish500 [490]

First, you gotta simplify. There’s really nothing to simplify so just take it out of the parenthesis.

2x-8=2x-4

Now turn the -8 into a +8. Add it on each side.

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Now turn the 2x on the right into a negative. Do the same thing you did with the 8.
Now it’s:

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That means there’s no solution.
Hope this helped :)

7 0

3 years ago

Solve the quadratic equation 6x^2-13x-28=0 by factoring.

mixer [17]

First step to factor the trinomial, multiply the constant -28 with the leading coefficient 6.

So, -28 * 6 = - 168.

Next step is to breakdown -168 into two multiples so that their addition will result the coefficient of w= - 13.

So, -168 = -21 * 8.

And addition of - 21 and 8 will give - 13.

So, next step is to replace -13x with -21x + 8. Therefore,

6x² - 21x + 8x - 28 =0

(6x² - 21x) + (8x - 28 )=0 Make the group of two terms.

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So, $x= \frac{7}{2} , -\frac{4}{3}$

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3 years ago

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Step-by-step explanation:

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