Answer:
240/sqrt(pi)
Step-by-step explanation:
We know that the area of a circle is $pi*r^2$, and we also know that the diameter of a circle is equal to $2r$.
Let's first make an equation for this problem.
pi*r^2=14400
Dividing both sides by pi, we get
r^2=14400/pi
Now, taking the square root of both sides gives us
r=120/sqrt(pi)
We are trying to find the diameter, which is twice the size of the radius.
Thus, we multiply the equation by two.
2r=240/sqrt(pi)
The resolvent is:
x = (- b +/- root (b2 - 4ac)) / 2a
To apply it we must have a polynomial of the form:
ax2 + bx + c = 0
Where,
One side of the equation is zero.
The polynomial must be only grade 2.
The coefficient a must be different from zero.
Answer:
options: B, C, D are correct
Step-by-step explanation:
the area = 
= 
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