Given : A florist currently makes a profit of $20 on each of her celebration bouquets and sells an average of 30 bouquets every week . and graph
To Find : Maximum profit , breakeven point , profit interval
Solution:
The maximum profit the florist will earn from selling celebration bouquets is $ 675
peak of y from Graph
The florist will break-even after Selling 20 one-dollar decreases.
at breakeven
Break even is the point where the profit p(x) becomes 0
The interval of the number of one-dollar decreases for which the florist makes a profit from celebration bouquets is (0 ,20).
after 20 , P(x) is - ve
Trapezoid and isocseles trapezoid
Answer:
The error is the exponent in the answer should be 11.
Step-by-step explanation:
When you move the decimal place one spot as they do in the final step to move it from a base 10 to a base 1, we have to add a exponent on. Therefore, it should go from 10 to 11.
Answer:
The equation of a line through (5 -3) that is parallel to y = 1/2 x+3 is
y = - 2 x + 7
Step-by-step explanation:
Let us assume the slope of the line whose equation we need to find is m 1.
The line parallel to the needed line is: y=1/2x+3
Comparing it with the general form: y = m x + C
we get m 2 = 1/2
Now, as Line 1 is Perpendicular to Line 2.
⇒ m 1 x m 2 = -1
⇒ m 1 x ( 1/2) = -1
⇒ m 1 = - 2
Also, the point son the line 1 is given as: (x,y) = (5,-3)
Put the value of point and Slope in y = m x + C to find the value of Y- INTERCEPT.
we get: -3 = (-2) (5) + C
or, C = -3 + 10 = 7
⇒ C = 7
The general line equation is given as: y = m x + C
Substituting the values of C and m, we get:
y = - 2 x + 7
Hence, the equation of a line through 5 -3 that is parallel to y = 1/2 x+3 is
y = - 2 x + 7
Answer:
it can be use in equation
An irrational number is a number that cannot be expressed as a fraction for any integers and. . Irrational numbers have decimal expansions that neither terminate nor become periodic.