Given:
Consider the expression are
1) 
2) ![\sqrt[3]{-8}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-8%7D)
3) 
4) ![\sqrt[3]{27}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D)
To find:
The simplified form of each expression.
Solution:
1. We have,
Therefore, the value of this expression is 6.
2. We have,
![\sqrt[3]{-8}=(-8)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-8%7D%3D%28-8%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\sqrt[3]{-8}=((-2)^3)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-8%7D%3D%28%28-2%29%5E3%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\sqrt[3]{-8}=(-2)^{\frac{3}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-8%7D%3D%28-2%29%5E%7B%5Cfrac%7B3%7D%7B3%7D%7D)
![\sqrt[3]{-8}=-2](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-8%7D%3D-2)
Therefore, the value of this expression is -2.
3. We have,
Therefore, the value of this expression is -10.
4. We have,
![\sqrt[3]{27}=(27)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D%3D%2827%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\sqrt[3]{27}=(3^3)^{\frac{1}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D%3D%283%5E3%29%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D)
![\sqrt[3]{27}=(3)^{\frac{3}{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D%3D%283%29%5E%7B%5Cfrac%7B3%7D%7B3%7D%7D)
![\sqrt[3]{27}=3](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B27%7D%3D3)
Therefore, the value of this expression is 3.
Yes, it does! evaluating and solving an expression are the same thing!
Answer: D. al of the above
Step-by-step explanation:
the numbers 1-7 are the significant figures, and if there is a zero but still three numbers ranging from 1-7, it counts
The answer to the question
Answer:
approx. 3 hours
Step-by-step explanation:
14 newspapers in 20 minutes means he can deliver 42 newspapers an hour.
60/42 = 1.4285 newspapers per minute
131 x 1.4285 = 187.1335 minutes = 3.1188 hours
