Answer:
making letters subject is only possible
with equations but not expression.
So the question has no solution.
Use the pythagorean theorem a.k.a

c is the hypotenuse while a & b are the legs


subtract 225 from 289

square root both b and 64
the other leg is equal to 8
The normal vector to the plane <em>x</em> + 3<em>y</em> + <em>z</em> = 5 is <em>n</em> = (1, 3, 1). The line we want is parallel to this normal vector.
Scale this normal vector by any real number <em>t</em> to get the equation of the line through the point (1, 3, 1) and the origin, then translate it by the vector (1, 0, 6) to get the equation of the line we want:
(1, 0, 6) + (1, 3, 1)<em>t</em> = (1 + <em>t</em>, 3<em>t</em>, 6 + <em>t</em>)
This is the vector equation; getting the parametric form is just a matter of delineating
<em>x</em>(<em>t</em>) = 1 + <em>t</em>
<em>y</em>(<em>t</em>) = 3<em>t</em>
<em>z</em>(<em>t</em>) = 6 + <em>t</em>
Answer:
-2 (filled in circle) to 7 (open circle)
Step-by-step explanation:
for the first equation x must be the equal to or smaller than 6. so -3(-2) equals 6 but anything less than -2, let's say -3(-3), will be BIGGER than six, so -2 including -2 which is a filled in circle.
solving it:
-3(x)
6


for the second equation x must be smaller than 17. so first you take out + 3 by subtracting it, leaving the equation as 2x<14. 2(7)<14 is NOT true so anything bigger than 7 leaves it as true because 6.98934747483 can still make it true, so anything smaller than 7 which is 7 with a not filled in, or open, circle
solving it:

2x < 14

x < 7
my explanation is all over the place, but hope this helps!!!