2 8 −10−15÷3=2, start superscript, 8, end superscript, minus, 10, minus, 15, divided by, 3, equals
Sergio039 [100]
Answer:
241
Step-by-step explanation:
Given the equation to evaluate :
2^8 −10−15÷3
2^8 = 256
256 - 10 - 15 ÷ 3
From BODMAS principle, we evaluate the divison before subtraction :
-15 ÷ 3 = - 5
256 - 10 -5
256 - 15
= 241
I don't recognize this problem, please make sure the input is complete.
Step-by-step explanation:
MID POINT =[(X1 +X2)/2 , (Y1 +Y2)/2]
WE KNKW THAT A(2,–8) AND THE MID POINT IS (3,3)
SUBSTITUTING INTO THE EQUATION ABOVE
(3,3) = [(2+ X2)/2 ,(–8+ Y2)/2]
EQUATING THE X COORDINATES
=> 3 = (2+ X2)/2 (CROSS MULTIPLY)
=> 6 = 2 + X2
X(subscript 2)= 4
EQUATING THE Y COORDINATES
=> 3 =(–8 +Y2)/2 (CROSS MULTIPLY)
6 = –8 +Y2
=> Y(subscript 2)= 14
THEREFORE THE COORDINATES OF B ARE (4 ,14)
hope this helps :)