Lily ran 1,000 meters in 12 minutes. How many meters/minute did she run?

You spent $145 purchasing 3 student tickets and 7 adult tickets. Adult tickets cost $5 more than a student ticket. Find the cost

vova2212 [387]

Answer:

$11 and $16

Step-by-step explanation:

let x be the cost of a student ticket then an adult ticket is x + 5 , then

3x + 7(x + 5) = 145 , that is

3x + 7x + 35 = 145

10x + 35 = 145 ( subtract 35 from both sides )

10x = 110 ( divide both sides by 10 )

x = 11

Student ticket costs $11 and adult ticket = x + 5 = 11 + 5 = $16

3 0

3 years ago

The school store opened on the first day of school with 45 notebooks and 15 pencils. Within two days it sold all of these items.

malfutka [58]

The number of pencils sold on the first day is 5 pencils.

The number of notebooks sold on the first day is 10 notebooks.

The number of pencils sold on the second day 10 pencils.

The number of notebooks sold on the second day 35 notebooks.

Step-by-step explanation:

Given data,

The total number of notebooks in the store = 45 notebooks.
The total number of Pencils in the store = 15 pencils.
The number of days that all items were sold = 2 days.

Now, you have to calculate the no.of notebooks and no. of pencils sold each day.

In the first day :

The number of sale of notebooks and pencils are given by,

Twice as many notebooks were sold as pencils.

Let us take, the number of pencils sold on the first day = x

And, the number of notebooks sold on the first day = 2x (Twice as pencils).

In the second day :

The number of sale of notebooks and pencils are given by,

For every 7 notebooks sold, 2 pencils were sold.

The number of pencils sold on the second day = 2y

The number of notebooks sold on the second day = 7y

The equation is framed for number of notebooks sold on each day :

The number of notebooks sold ⇒ 2x + 7y = 45 -------(1)

The equation is framed for number of pencils sold on each day :

The number of pencils sold: x + 2y = 15 ----------(2)

Solving the equations by multiplying eq(2) by 2 and subtract it from eq(1),

2x + 7y = 45

- (2x + 4y) = 30

3y = 15

⇒ y = 15/3

⇒ y = 5

The value of y is 5.

Substitute y=5 in eq (2),

⇒ x + 2(5) = 15

⇒ x + 10 = 15

⇒ x = 15 - 10

⇒ x = 5

The value of x is 5.

First day sale,

The number of pencils sold on the first day = x ⇒ 5 pencils

The number of notebooks sold on the first day = 2x ⇒ 10 notebooks

Second day sale,

The number of pencils sold on the second day = 2y ⇒ 10 pencils

The number of notebooks sold on the second day = 7y ⇒ 35 notebooks.

8 0

3 years ago

To make the expression 4x-2 + (2x + 4) equivalent to 2(6x + 7), what must be the value in the box?

podryga [215]

$4x - 2 + (2x + 4) = 2(6x + 7) \\$

$4x - 2 + 2x + 4 = 12x + 14$

Simplification

$6x + 2 = 12x + 14$

Subtract sides 2

$6x + 2 - 2 = 12x + 14 - 2$

Simplification

$6x = 12x + 12$

Subtract sides -12x

$6x - 12x = 12x - 12x + 12$

Simplification

$- 6x = 12$

Divided sides by -6

$\frac{ - 6}{ - 6}x = \frac{12}{ - 6} \\$

$x = - 2$

It is must be in the box buddy.

And we're done...♥️♥️♥️♥️♥️

5 0

3 years ago

Town B is 6 miles due north of town A, and town C is due east of town A. It is 11 miles from town B to town C. Find the distance

nadya68 [22]

Answer:

12.53 miles

Step-by-step explanation:

6² + 11² = x²

36 + 121 = x²

157 = x²

x = 12.53 miles

4 0

3 years ago

Read 2 more answers

Can a math god help me out?

Taya2010 [7]

Answer:

$f(1)=70$

$f(n)=f(n-1)+6$

Step-by-step explanation:

One is given the following function:

$f(n)=64+6n$

One is asked to evaluate the function for $(f(1))$ , substitute $(1)$ in place of $(n)$ , and simplify to evaluate:

$f(1)=64+6(1)$

$f(1)=64+6$

$f(1)=70$

A recursive formula is another method used to represent the formula of a sequence such that each term is expressed as a function of the last term in the sequence. In this case, one is asked to find the recursive formula of an arithmetic sequence: that is, a sequence of numbers where the difference between any two consecutive terms is constant. The following general formula is used to represent the recursive formula of an arithmetic sequence:

$a_n=a_(_n_-_1_)+d$

Where ( $a_n$ ) is the evaluator term ( $a_(_n_-_1_)$ ) represents the term before the evaluator term, and (d) represents the common difference (the result attained from subtracting two consecutive terms). In this case (and in the case for most arithmetic sequences), the common difference can be found in the standard formula of the function. It is the coefficient of the variable (n) or the input variable. Substitute this into the recursive formula, then rewrite the recursive formula such that it suits the needs of the given problem,

$a_n=a_(_n_-_1_)+d$

$a_n=a_(_n_-_1_)+6$

$f(n)=f(n-1)+6$

3 0

3 years ago