Lily ran 1,000 meters in 12 minutes. How many meters/minute did she run?

53% of U.S. adults have very little confidence in newspapers. You randomly select 10 U.S. adults. Find the probability that the

faltersainse [42]

Answer:

a

$P(X = 5) = 0.2423$

b

$P( X \ge 6 )= 0.4516$

c

$P( X < 4 )= 0.12694$

Step-by-step explanation:

From the question we are told that

The population proportion is p = 0.53

The sample size is n = 10

Generally the distribution of the confidence of US adults in newspapers follows a binomial distribution

i.e

$X \~ \ \ \ B(n , p)$

and the probability distribution function for binomial distribution is

$P(X = x) = ^{n}C_x * p^x * (1- p)^{n-x}$

Here C stands for combination hence we are going to be making use of the combination function in our calculators

Generally the probability that the number of U.S. adults who have very little confidence in newspapers is exactly five is mathematically represented as

$P(X = 5) = ^{10}C_5 * 0.53^5 * (1- 0.53)^{10-5}$

=> $P(X = 5) = 252 * 0.04182 * 0.023$

=> $P(X = 5) = 0.2423$

Generally the probability that the number of U.S. adults who have very little confidence in newspapers is at least six is mathematically represented as

$P( X \ge 6 )= P( X = 6) + P( X = 7) + P( X = 8) + P( X = 9) + P( X = 10)$

=> $P( X \ge 6 )= [^{10}C_6 * [0.53]^6 * (1- 0.53)^{10-6}] + [^{10}C_7 * [0.53]^7 * (1- 0.53)^{10-7}] + [^{10}C_8 * [0.53]^8 * (1- 0.53)^{10-8}] + [^{10}C_9 * [0.53]^9 * (1- 0.53)^{10-9}] + [^{10}C_{10} * [0.53]^{10} * (1- 0.53)^{10-10}]$

=> $P( X \ge 6 )= [0.227] + [0.1464] + [0.0619] + [0.0155] + [0.00082]$

=> $P( X \ge 6 )= 0.4516$

Generally the probability that the number of U.S. adults who have very little confidence in newspapers is less than four is mathematically represented as

$P( X < 4 )= P( X = 3) + P( X = 2) + P( X = 1) + P( X = 0)$

=> $P( X < 4 )= [^{10}C_3 * 0.53^3 * (1- 0.53)^{10-3}] + [^{10}C_2 * 0.53^2 * (1- 0.53)^{10-2}] + [^{10}C_1 * 0.53^1 * (1- 0.53)^{10-1}] + [^{10}C_0 * 0.53^0 * (1- 0.53)^{10-0}]$

=> $P( X < 4 )= 0.09051 + 0.03 + 0.0059 + 0.000526$

=> $P( X < 4 )= 0.12694$

5 0

2 years ago

Which is the correct formula for the function?

irakobra [83]

Answer:

y = -3x -1

Step-by-step explanation:

the slope is -3 and the y-intercept is -1

8 0

2 years ago

The state medical school has discovered a new test for tuberculosis. (If the test indicates a person has tuberculosis, the

Inessa [10]

The probability according to the given scenario is:

(a) 0.0395

(b) 0.95

(c) 0.076

The given values are:

$P(B/A) = 0.79$
$P(A) = 0.05$

(a)

The probability that the b/w has tuberculosis as well as having (+) test will be:

→ $P(A \cap B) = P(B/A).P(A)$

By substituting the values, we get

→ $= 0.79\times 0.05$

→ $= 0.0395$

(b)

The probability that a person does not have tuberculosis will be:

→ $P(A') = 1-P(A)$

→ $=1-0.05$

→ $= 0.95$

(c)

The person does not have tuberculosis as well as have a (+) test, the probability will be:

→ $P(A' \cap B) = P(A').P(B/A')$

→ $= 0.95\times 0.08$

→ $= 0.076$

Learn more:

brainly.com/question/14816227

8 0

1 year ago

Solve this equation. 5n+7=7(n+1)-2n

9966 [12]

Distribute 7 to both n and 1

7(n + 1) = 7n + 7

5n + 7 = 7n + 7 - 2n

Combine like terms

5n + 7 = 7n - 2n + 7

5n + 7 = 5n + 7

If you want to solve for n, subtract 7 from both sides

5n + 7 (-7) = 5n + 7 (-7)

5n = 5n

then divide 5 from both sides

5n/5 = 5n/5

n = n

Effectively, this equation is unsolvable

hope this helps

3 0

2 years ago

Read 2 more answers

What is one tenth of two hundred

matrenka [14]

First you have to convert 1/10 into a decimal:
1/10= 0.1
Multiply 0.1 by 200:
0.1x200=20
So, 20 is 1/10 of 200.

6 0

3 years ago