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3 years ago

(07.05 HC)

1 answer:

6 0

The step she did wrong was step 1 -2 when she did the distributive property wrong. The correct step should be step 2: 9y-24=10+3y

Good luck mate :P cheers

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One of the slowest fish is the blenny

Gwar [14]

Answer:

It swims 1.75 miles in 3.5 hours. X stands for hours so x=3.5. Y stands for miles so y=1.75.

Step-by-step explanation:

your equation is y=0.5x

we know x=3.5

so y= 0.5(3.5)

solve and you get y= 1.75

so in (x,y) intercept format (3.5,1.75) and you can make a graph and label your x intercepts hours and your y intercepts miles traveled.

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2 years ago

At the last basketball game ,12 out of the first 48 people who entered the stands were wearing a coat. if this sample is represe

erma4kov [3.2K]

Answer: attending the game

Step-by-step explanation:

Given: 12 out of the first 48 people who entered the stands were wearing a coat.

That means, Proportion of people wearing coat = $\dfrac{12}{48}=\dfrac{1}{4}$ (People wearing coat divided by Total people)

Total people in the sample attending the game= 200

Number of people wearing a coat = $200\times\dfrac14$

$=50$

Hence, 50 people are wearing a coat.

6 0

2 years ago

Using the following information = Universal set = {2,3,4,5,6,7,8,9,12,13,14,16,20,22,56). Subset A = {9,12,13,20,22,56); Subset

Cloud [144]

$\dfrac{2}{5},\dfrac{13}{15},\dfrac{3}{5},\dfrac{1}{5},\dfrac{1}{5}$

step-by-step explanation:

The intersection of two sets A and B, denoted by A ∩ B, is the set containing all elements of A that also belong to B.

The union (denoted by ∪) of a collection of sets is the set of all elements in the collection.

$P(s)$ of a set $s$ is defined as ratio of number of elements in $s$ to the number of elements in $universal set$

given $Universalset=$ $\{$ $\text{2,3,4,5,6,7,8,9,12,13,14,16,20,22,56}$ $\}$

given $A=\{9,12,13,20,22,56\}$ and $H=\{4,5,8,9,16,22\}$

and $C=\{1,4,20,22,56\}$

For Question A:

$A$ ∩ $H$ = $\{9,12,13,20,22,56\}$ ∩ $\{4,5,8,9,16,22\}$

= $\{9,22}\}$

( $A$ ∩ $H$ )∪ $C$ = $\{9,22}\}$ ∪ $C=\{1,4,20,22,56\}$ = $\{1,4,9,20,22,56\}$

$p((A$ ∩ $H)$ ∪ $C)$ = $\frac{6}{15}=\frac{2}{5}$

For Question B:

$H$ ∩ $C$ = $\{4,22\}$

$p(H$ ∩ $C)$ '= $\frac{15-2}{15}=\frac{13}{15}$

For Question C:

$p(H)$ '= $\frac{15-6}{15}=\frac{3}{5}$

For Question D:

$C$ \ $H$ = $\{1,20,56\}$

$p(C$ \ $H)$ = $\frac{3}{15}=\frac{1}{5}$

For Question E:

$A$ \ $C$ = $\{9,12,13\}$

$p(A$ \ $C)$ = $\frac{3}{15}=\frac{1}{5}$

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3x to the second power plus 5x plus 1

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2 years ago