Dimensions are length 20 meter and width 14 meter
<em><u>Solution:</u></em>
Let "a" be the length of rectangle
Let "b" be the width of rectangle
Given that,
<em><u>A rectangle has width that is 6 meters less than the length</u></em>
Width = length - 6
b = a - 6
The area of the rectangle is 280 square meters
<em><u>The area of the rectangle is given by formula:</u></em>

<em><u>Substituting the values we get,</u></em>

<em><u>Solve the above equation by quadratic formula</u></em>



Since, length cannot be negative, ignore a = -14
<em><u>Thus solution of length is a = 20</u></em>
Therefore,
width = length - 6
width = 20 - 6 = 14
Thus dimensions are length 20 meter and width 14 meter
Hello!
We know that mike can bind 109 flowers per hour.
Lets create an equation to remember this.
<u>Mikes equation: </u>
<u>109x = y</u>
<u />
<x is representing per hour in this math problem>
We know that John can bind 116 flowers per hour, here is his equation.
<u>Johns equation:</u>
<u>116x = y</u>
<u />
Question: If they work together for 5 hours, how many flowers can they bind?
First, plug in the number five in both equations.
Second, solve the equation by multiplying.
Mikes:
109(5) = y
109 times 5 is 545
y = 545
Johns:
116(5) = y
116 times 5 is 580
y = 580
We want to know how many flowers can they bind if they work together.
This means we need to add the answers of the equations from both mike's and john's together.
545 + 580 = 1,125
The answer is 1,125
Step one: (((x2)+x)+1)+((0-(2x23•x))+5)
Step two: Check for a perfect cube. 2.1 -2x24+x2+x+6 is not a perfect cube.
2.2 Factoring: -2x24+x2+x+6
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: x+6
Group 2: -2x24+x2
Pull out from each group separately :
Group 1: (x+6) • (1)
Group 2: (2x22-1) • (-x2)
The groups have no common factor and can not be added up to form a multiplication.
So the answer would be, -2 (x24) + (x2) ++ 6.
To calculate the IQR, we need the radian, which is the middle number of each column, namely (86,82) for each exam.
Above the middle number, we have 5 values. The middle value (of the upper part) is Q3, which is on the third line, or (92,85).
Below the middle number, we also have 5 values. The middle (of the lower half) is Q1, which is on the 9th line (80,78)
The IQR is the difference between Q3 and Q1, namely
(92-80, 85-78) = (12, 7)
Since 12>7, we conclude that the IQR of the mid-term is higher than the final.
Answer:
1,848
Step-by-step explanation:
