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2 years ago

2. Find the base of a triangle which has an area of 2 1/4 square inches, and a height of 1/8 in.

Mathematics

1 answer:

Maslowich2 years ago

7 0

Answer:

36 inches

Step-by-step explanation:

Given data

Area of triangle =2 1/4 square inches

Area =9/4 square inches

Height of triangle =1/8 inches

We know that the expression for the area of triangle is

Area = 1/2Base *Height

9/4=1/2*Base *1/8

9/4=Base/16

Cross multiply

16*9=Base*4

144=Base*4

Base =144/4

Base=36 inches

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3 years ago

Solve the system of equations. x+y=4 y=x^2 - 8x + 16 a) {(-3,7).(-4, 8)} b) [(4,0)} c) {(3,1),(4,0) d) {(3,7). (4.0)} e) none

Marysya12 [62]

Answer: The required solution of the given system is

(x, y) = (3, 1) and (4, 0).

Step-by-step explanation: We are given to solve the following system of equations :

$x+y=4~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\y=x^2-8x+16~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)$

From equation (i), we have

$x+y=4\\\\\Rightarrow y=4-x~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)$

Substituting the value of y from equation (iii) in equation (ii), we get

$y=x^2-8x+16\\\\\Rightarrow 4-x=x^2-8x+16\\\\\Rightarrow x^2-8x+16-4+x=0\\\\\Rightarrow x^2-7x+12=0\\\\\Rightarrow x^2-4x-3x+12=0\\\\\Rightarrow x(x-4)-3(x-4)=0\\\\\Rightarrow (x-3)(x-4)=0\\\\\Rightarrow x-3=0,~~~~~~~x-4=0\\\\\Rightarrow x=3,~4.$

When, x = 3, then from (iii), we get

$y=4-3=1.$

And, when x = 4, then from (iii), we get

$y=4-4=0.$

Thus, the required solution of the given system is

(x, y) = (3, 1) and (4, 0).

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3 years ago

2. Find the base of a triangle which has an area of 2 1/4 square inches, and a height of 1/8 in. ​

2. Find the base of a triangle which has an area of 2 1/4 square inches, and a height of 1/8 in.