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Alex
3 years ago
14

Find the equation of the straight line passing through the points (2,-4) and (1,0)

Mathematics
1 answer:
myrzilka [38]3 years ago
4 0

Answer:

4x + y = 4

Step-by-step explanation:

Firstly calculate your gradient

;Gradient = (-4 - 0)/(2 - 1)

;Gradient = -4

Then use the formula;

y - y(y - coordinate of any of the two points given) = Gradient(x - x(x - coordinate of any of the two points given but must be from the same point as that you used in your y - coordinate))

; y - (-4) = -4(x - 2)

; y + 4 = -4x + 8

;Equation of the line..,

4x + y = 4

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NEED HELP GIVING BRAINLIEST
Pie

For this case we have by definition, that the equation of a line in the slope-intersection form is given by:

y = mx + b

Where:

m: It's the slope

b: It is the cutoff point with the y axis

We need two points through which the line passes to find the slope:

(0, -4)\\(1,0)

We found the slope:

m = \frac {y2-y1} {x2-x1}\\m = \frac {0 - (- 4)} {1-0} = \frac {4} {1} = 4

So, the equation is of the form:

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We substitute a point to find "b":

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