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3 years ago

What are the endpoint coordinates for the midsegment of △BCD that is parallel to BC¯¯¯¯¯?

Mathematics

2 answers:

wariber [46]3 years ago

7 0

Answer:

The perfect person does not ex---False

Thank you so much man, great help for us people facing brain farts.

Step-by-step explanation:

Eddi Din [679]3 years ago

5 0

Answer:

The endpoint coordinates for the mid segment of △BCD that is parallel to BC are (-2,-1) and (1,0).

Step-by-step explanation:

The mid segment of a triangle a line segment that connecting the midpoint of two sides and parallel to the third side.

It is given that mid segment is parallel to BC, it means it is connecting the midpoints of BD and CD.

The midpoint formula,

$Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

$\text{Midpoint of BD}=(\frac{-3-1}{2},\frac{1-3}{2})=(-2,-1)$

$\text{Midpoint of CD}=(\frac{3-1}{2},\frac{3-3}{2})=(1,0)$

Therefore the endpoint coordinates for the mid segment of △BCD that is parallel to BC are (-2,-1) and (1,0).

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3 years ago

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iren [92.7K]

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2 years ago

The slope of the line below is -1. write the point-slope equation of the line using the coordinates of the labeled point.

omeli [17]

Answer:

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Step-by-step explanation:

Point Slope Form is:

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When:

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3 years ago

Read 2 more answers

Which system is equivalent to

sammy [17]

Answer:

D) 6x^2 - 8y^2 = 50

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Step-by-step explanation:

We are given the following two expressions:

$3x^2-4y^2=25$

and

$-6x^2-2y^2=11$

Now if we look at the option D) $6x^2 - 8y^2 = 50
$ and $-6x^2 - 2y^2 = 11$ , we can observe that the earlier part in the given expression is just a simplification of 6x^2 - 8y^2 = 50.

$6x^2 - 8y^2 = 50\\\\2(3x^2-4y^2) = 50\\\\3x^2-4y^2 = \frac{50}{2} \\\\3x^2-4y^2=25$

and the later part $-6x^2 - 2y^2 = 11$ is already the same.

Therefore, the correct answer option is D) 6x^2 - 8y^2 = 50

-6x^2 - 2y^2 = 11.

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3 years ago

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