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lesantik [10]
3 years ago
6

What are the endpoint coordinates for the midsegment of △BCD that is parallel to BC¯¯¯¯¯?

Mathematics
2 answers:
wariber [46]3 years ago
7 0

Answer:

The perfect person does not ex---False

Thank you so much man, great help for us people facing brain farts.

Step-by-step explanation:


Eddi Din [679]3 years ago
5 0

Answer:

The endpoint coordinates for the mid segment of △BCD that is parallel to BC are (-2,-1) and (1,0).

Step-by-step explanation:

The mid segment of a triangle a line segment that connecting the midpoint of two sides and parallel to the third side.

It is given that mid segment is parallel to BC, it means it is connecting the midpoints of BD and CD.

The midpoint formula,

Midpoint=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

\text{Midpoint of BD}=(\frac{-3-1}{2},\frac{1-3}{2})=(-2,-1)

\text{Midpoint of CD}=(\frac{3-1}{2},\frac{3-3}{2})=(1,0)

Therefore the endpoint coordinates for the mid segment of △BCD that is parallel to BC are (-2,-1) and (1,0).

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SOMEONE PLEASE ANSWER THIS FOR MY FIFTH GRADE COUSIN...IM NOT SMARTER THAN A FIFTH GRADER CLEARLY
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Answer:

AJ picks 252 pounds

Step-by-step explanation:

Lets define the following letters for each name:

A is AJ  

B is Blaze

L is Laurence

J is Jack

Now we will analyze the phrases one by one:

Blaze picks three times as many as Laurence means:

B = 3 * L

Jack picks twice as many as Blaze.  

J = 2 * B, ans using the previous one lets substitute B with 3 * L

J = 2 * B = 2 * (3 * L)

J = 6 * L

Aj picks three times as many as Laurence.  

A = 3 * L

The total weight of the oranges is 1092 pounds.  

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We replace A, B & J in the last equation, with the previous results:

A + B + J + L = 1092

(3*L) + (3*L) + (6*L) + L = 1092, grouping using L as common factor:  

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L = 1092 / 13

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A = 3 * L = 3 * 84 = 252 pounds (for Aj)

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J = 6 * L = 6 * 84 = 504 pounds (for Jack)

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