The description which accurately represents a water molecule is slightly negative oxygen pole, slightly positive hydrogen poles.
Water is a polar molecule. This means that the molecule has a dipole moment.
The polarity of water arises from the difference in electronegativity between hydrogen and oxygen.
Hence, in water molecule, oxygen is slightly negative and hydrogen is slightly positive thereby resulting in a dipole.
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The solubility of nitrogen gas in water is 1.90 mL/dL at 1.00 atm and 13.3 mL/dL at 7.00 atm.
We want to relate the solubility of a gas with its partial pressure.
We can do so using Henry's law.
<h3>What does Henry's law state?</h3>
Henry's law states that the amount of dissolved gas in a liquid is proportional to its partial pressure above the liquid.
C = k × P
where,
- C is the concentration of a dissolved gas.
- k is the Henry's Law constant.
- P partial pressure of the gas.
The solubility of nitrogen gas is 1.90 mL/dL of blood at 1.00 atm.
Since the solvent is basically water, we can understand that the concentration of nitrogen gas is 1.90 mL/dL at 1.00 atm.
We can use this information to calculate Henry's Law constant.
k = C/P = (1.90 mL/dL)/1.00 atm = 1.90 mL/dL.atm
We want to calculate the solubility of nitrogen gas at a pressure of 7.00 atm.
We will use Henry's law.
C = k × P = (1.90 mL/dL.atm) × 7.00 atm = 13.3 mL/dL
The solubility of nitrogen gas in water is 1.90 mL/dL at 1.00 atm and 13.3 mL/dL at 7.00 atm.
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Answer: option C) II < III < I
i.e [OH−] < [H3O+] < I
Explanation:
First, obtain the pH value of I and II, then compare both with III.
For I
Recall that pH = -log (H+)
So pH3O = -log (H3O+)
= - log (1x10−5)
= 4
For II
pOH = - log(OH-)
= - log(1x10−10)
= 9
For III
pH = 6
Since, pH range from 1 to 14, with values below 7 to be acidic, 7 to be neutral, above 7 to be alkaline: then, 9 < 6 < 4
Thus, the following solutions from least acidic to most acidic is II < III < I
Answer:
it's B
Explanation:
number of grams mineral salt in one is also the description of the salinity of ocean water
If it is saturated compound then we can calculate the double bond equivalent which will be equal to the number of rings in the compound
the double bond equivalent can be calculated using following formula
Where
H = number of Hydrogen atoms
C = number of carbon atoms
X= number of halogen atoms
N = number of nitrogen atoms
DBE = (10 + 1 - 16 / 2 ) = 3
Hence there are three rings in the compound
