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3 years ago

What is the process where a solid changes directly into a gas without first turning into a liquid?

2 answers:

6 0

Tip for next time, when you are looking at these things, rather than just posting it, take a look at your options. A solid to a gas, this means that melting cant be an option because that is solid to a liquid, evaporation cant be an option because that is liquid to a gas and condensation cant be because that is gas to a l. Therefore the answer must be sublimatio.

Snezhnost [94]3 years ago

3 0

It's 100% "b. sublimation" i just took the test in Time4Learning.

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Using complete sentences, explain how to predict the products and balance the reaction between sulfuric acid and potassium hydro

My name is Ann [436]

Answer:

The answer to your question is given below.

Explanation:

The reaction of sulfuric acid and potassium hydroxide is called neutralisation.

Neutralisation is a reaction involving an acid and a base which produces salt and water only.

For the react between sulfuric acid, H2SO4 and potassium hydroxide, KOH, we can predict the products obtained as follow:

H2SO4 + KOH —>

In solution, H2SO4 and KOH will dissociate as follow:

H2SO4(aq) —> 2H^+(aq) + SO4^2-(aq)

KOH(aq) —> K^+(aq) + OH^-(aq)

H2SO4 + KOH —>

2H^+(aq) + SO4^2-(aq) + K^+(aq) + OH^-(aq) —> K^+(aq) + SO4^2-(aq) + 2H^+(aq) + OH^-

H2SO4 + KOH —> K2SO4 + H2O

Now, we can balance the above equation as follow:

H2SO4 + KOH —> K2SO4 + H2O

There are 2 atoms K on right side and 1 atom on the left side. It can be balance by writing 2 in front of ko as shown below:

H2SO4 + 2KOH —> K2SO4 + H2O

There are 2 atoms of H on the right side and a total of 4 atoms on the left side. It can be balance by writing 2 in front of H2O as shown below:

H2SO4 + 2KOH —> K2SO4 + 2H2O

Now,the equation is balanced.

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4 years ago

Most strings of outdoor lights are wired in a parallel circuit. Which of the following is the best reason why a string of outdoo

sergey [27]

Answer:

C.If one light in the string burns out in a parallel circuit, the rest of the lights will continue to shine.

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3 years ago

Concerning the rate law, Rate = K[A]²[B], what are appropriate units for the rate<br> constant k?

vovikov84 [41]

The correct answer is M^-1s^-1.

The proportionality constant in the rate law expression, known as the rate constant or the particular rate constant, represents the relationship between the rate of the reaction and the concentration of the reacting species. Because it equals the rate of the reaction when the concentration of the reactants is assumed to be unity, it is known as the specific rate constant. The speed and direction of a chemical reaction are measured by a reaction rate constant. We are aware that the values of the Rate constant vary with temperature.

The given rate law is:

Rate = k[A][B]

The units of rate are always Ms^-1 and the units of [a] are mol so: mol*s^-1

Putting the units in the given rate law:

Rate = k[A][B]

Ms^-1=k×(M)×(M)

k=Ms^-1/M^2

k=M^-1s^-1

To learn more about rate law refer the link:

brainly.com/question/14779101

#SPJ9

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2 years ago