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tino4ka555 [31]
3 years ago
12

The final velocity of an object moving in one dimension is given by the formula v = u + at, where u is the initial velocity, a i

s the acceleration, and t is the time.
Solve this equation for a.

a = (v + u)/t

a = t(v + u)

a = t(v – u)

a = (v – u)/t
Mathematics
2 answers:
andrezito [222]3 years ago
7 0

Answer:

A=(V-U)/T

IS THE ANSWER ON E2020 JUST FINISHED

Step-by-step explanation:

Nady [450]3 years ago
5 0

Answer:

The answer is a=(v-u)/t or D on edge 2020

Step-by-step explanation:

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b. 11/25

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We proceed as follows;

From the question, we have the following information;

Three urns A, B and C contains ( 3 black balls 7 white balls), (7 black balls and 13 white balls) and (12 black balls and 8 white balls) respectively.

Now,

Since events of choosing urn A, B and C are denoted by Ai , i=1, 2, 3

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So, P(A1) =x =1/5 , ....(3)

P(A2) = 2x= 2/5 and ....(4)

P(A3) = 2x= 2/5 ...(5)

Also urns A, B and C has total balls = 10, 20 , 20 respectively.

Now, if we choose one urn and then pick up 2 balls randomly then;

(a) Probability that the first ball is black

=P(A1)×P(Back ball from urn A) +P(A2)×P(Black ball from urn B) + P(A3)×P(Black ball from urn C)

= (1/5)×(3/10) + (2/5)×(7/20) + (2/5)×(12/20)

= (3/50) + (7/50) + (12/50)

=22/50

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(b) The Probability that the first ball is black given that the second ball is white is same as the probability that first ball is black (11/25). This is because the event of picking of first ball is independent of the event of picking of second ball.

Although the event picking of the second ball is dependent on the event of picking the first ball.

Hence, probability that the first ball is black given that the second ball is white is 11/25

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