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3 years ago

PLS ANSWER WILL GIVE BRAINLIEST!

Mathematics

1 answer:

IgorLugansk [536]3 years ago

7 0

Answer:

I think so the 4 th one....

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Assume a trucker changes his tire every 40,000 miles, and that he starts with a brand new set of tires, how many sets of tires w

anyanavicka [17]

40 sets of tires. I learned this by looking up your question because it is incomplete.

6 0

3 years ago

Anyone know the answer to this?

stira [4]

Answer:

124.80 ft

Step-by-step explanation:

Height of Daniel = 6 ft

The angle of elevation from his eyes to the top of the statue is = 68°

Daniel is 48 ft away from the base of the statue

To find the height of the statue apply the tangent of an angle formula then add height of Daniel as;

Tan 68° = h/48

h= {48 tan 68°} + 6 ft

h= 124.804168964

h= 124.80 ft

4 0

3 years ago

Order the numbers from least to greatest. -7/5, -1 5/11, -1.45, -1 91/200

Anna35 [415]

Answer:

Step-by-step explanation:

-7/5=-1.400

-1 5/11=-16/11=-1.455...

-1.450

-1 91/200=-291/200=-1.405

-1.455 <-1.450 <-1.405 <-1.400

- 1 5/11 <-1.45 <- 91/200 <-7/5

7 0

4 years ago

A group of 45 students, 26 boys and 19 girls, are hanging out in the high school cafeteria after school, 11 boys play basketball

balu736 [363]

Answer:

27 out of 45 (27/45)

Step-by-step explanation:

1) 45 student = 26 boys and 19 girls

2) 11 boys + 7 girls = 18 students

3) Therefore the probability of not picking a basketball player would be 27 because 27 students do not play basketball.

8 0

4 years ago

A quality control expert at Glotech computers wants to test their new monitors. The production manager claims they have a mean l

tankabanditka [31]

Answer:

The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors

P(X⁻ ≥ 96.3) = 0.0087

Step-by-step explanation:

Step(i):-

Given that the mean of the Population = 95

Given that the standard deviation of the Population = 5

Let 'X' be the random variable in a normal distribution

Let X⁻ = 96.3

Given that the size 'n' = 84 monitors

Step(ii):-

The Empirical rule

$Z = \frac{x^{-} -mean}{\frac{S.D}{\sqrt{n} } }$

$Z = \frac{96.3 - 95}{\frac{5}{\sqrt{84} } }$

Z = 2.383

The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors

P(X⁻ ≥ 96.3) = P(Z≥2.383)

= 1- P( Z<2.383)

= 1-( 0.5 -+A(2.38))

= 0.5 - A(2.38)

= 0.5 -0.4913

= 0.0087

Final answer:-

The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors

P(X⁻ ≥ 96.3) = 0.0087

3 0

3 years ago