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Blababa [14]
3 years ago
11

One day when Terry went to school the temperature outside was –15 degrees Fahrenheit. In Terry's classroom the temperature was 6

8 degrees Fahrenheit. How many more degrees was it inside the building than outside?
A. +83 degrees
B. +53 degrees
C. –83 degrees
D. –53 degrees
Mathematics
2 answers:
Dominik [7]3 years ago
7 0
Well, to find the answer to this problem you have to change the -15 to a positive (+15) and add the two numbers together. And, 15 + 68 = +83 degrees.

So, your answer is: A. +83 degrees.

It's really easy because all your doing is changing the -15 to a positive 15 and adding the two numbers together to get your answer.

Hope I helped!

- Debbie
Mariana [72]3 years ago
7 0
If you would like to know how many more degrees was it inside the building than outside, you can calculate this using the following step:

68 degrees Fahrenheit - (-15 degrees Fahrenheit) = 68 - (-15) = 68 + 15 = 83 degrees Fahrenheit

The correct result would be A. +83 degrees.
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Answer:

d = 8.602325
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(X1, Y1) = (1, 4)
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3 years ago
Taking a test i don’t know anything about please help
PilotLPTM [1.2K]

Answer:

See below for answers and explanations

Step-by-step explanation:

<u>Problem 4:</u>

The line of regression is \hat y = a+bx where:

a=\overline y-b \overline x

b=\frac{r*s_y}{s_x}

We are given that \overline y=75, s_y=8, \overline x=280, s_x=30, and r=0.60, therefore our slope, b, is:

b=\frac{r*s_y}{s_x}

b=\frac{(0.60)(8)}{30}

b=0.16

Therefore, the slope of the regression line is 0.16, which can be used along with the values of \overline y and \overline x to find the constant a:

a=\overline y-b \overline x

a=75-(0.16)(280)

a=30.2

This means our final regression line is \hat y = 30.2 + 0.16x

<u>Problem 5:</u>

The slope, b=0.16, means that for every 1 point earned for a student's pre-exam total, their final exam score will increase by 0.16 points for each point they earned on the pre-exam.

<u>Problem 6:</u>

The y-intercept (or constant), a=30.2, means that if a student's pre-exam total were 0, then they would expect to get a 30.2 on the final exam.

<u>Problem 7:</u>

R^{2}=(0.60)^{2}=0.36=36\%

<u>Problem 8:</u>

The fraction of variability (aka. coefficient of determination), R^2, means that a certain proportion (or percentage) of the variance in the response variable can be explained by the explanatory variable. In context, this means that 36% of the variance in final exam scores can be explained by the pre-exam scores.

6 0
3 years ago
Please help! see attached
nikdorinn [45]

Answer:

  1. The lowest value of the confidence interval is 0.5262 or 52.62%
  2. The highest value of the confidence interval is 0.5538 or 55.38%

Step-by-step explanation:

Here you estimate the proportion of people in the population that said did not have children under 18 living at home.It can also be given as a percentage.

The general expression to apply here is;

C.I=p+-z*\sqrt{\frac{p(1-p)}{n} }

where ;

p=sample proportion

n=sample size

z*=value of z* from the standard normal distribution for 95% confidence level

Given;

n=5000

<u>Find p</u>

From the question 54% of people chosen said they did not have children under 18 living at home

\frac{54}{100} *5000 = 2700\\\\p=\frac{2700}{5000} =0.54

<u>To calculate the 95% confidence interval, follow the steps below;</u>

  • Find the value of z* from the z*-value table

The value of z* from the table is 1.96

  • calculate the sample proportion p

The value of p=0.54 as calculated above

  • Find p(1-p)

0.54(1-0.54)=0.2484

  • Find p(1-p)/n

Divide the value of p(1-p) with the sample size, n

\frac{0.2448}{5000} =0.00004968

  • Find the square-root of p(1-p)/n

=\sqrt{0.00004968} =0.007048

  • Find the margin of error

Here multiply the square-root of p(1-p)/n by the z*

=0.007048*1.96=0.0138

The 95% confidence interval for the lower end value is p-margin of error

=0.54-0.0138=0.5262

The 95% confidence interval for the upper end value is p+margin of error

0.54+0.0138=0.5538

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Rudik [331]

Answer:

Step-by-step explanation:

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