One day when Terry went to school the temperature outside was –15 degrees Fahrenheit. In Terry's classroom the temperature was 6
8 degrees Fahrenheit. How many more degrees was it inside the building than outside?
A. +83 degrees
B. +53 degrees
C. –83 degrees
D. –53 degrees
2 answers:
Well, to find the answer to this problem you have to change the -15 to a positive (+15) and add the two numbers together. And, 15 + 68 = +83 degrees.
So, your answer is: A. +83 degrees.
It's really easy because all your doing is changing the -15 to a positive 15 and adding the two numbers together to get your answer.
Hope I helped!
- Debbie
If you would like to know how many more degrees was it inside the building than outside, you can calculate this using the following step:
68 degrees Fahrenheit - (-15 degrees Fahrenheit) = 68 - (-15) = 68 + 15 = 83 degrees Fahrenheit
The correct result would be A. +83 degrees.
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OD22264 is the correct answer for that
The distance between two points on the plane is given by the formula below
![\begin{gathered} A=(x_1,y_1),B=(x_2,y_2) \\ \Rightarrow d(A,B)=\sqrt[]{(x_1-x_2)^2+(y_1-y_2)^2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20A%3D%28x_1%2Cy_1%29%2CB%3D%28x_2%2Cy_2%29%20%5C%5C%20%5CRightarrow%20d%28A%2CB%29%3D%5Csqrt%5B%5D%7B%28x_1-x_2%29%5E2%2B%28y_1-y_2%29%5E2%7D%20%5Cend%7Bgathered%7D)
Therefore, in our case,

Thus,
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Therefore, the answer is sqrt(61)
In general,

Remember that

Therefore,