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jekas [21]
3 years ago
13

Taking a test i don’t know anything about please help

Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
6 0

Answer:

See below for answers and explanations

Step-by-step explanation:

<u>Problem 4:</u>

The line of regression is \hat y = a+bx where:

a=\overline y-b \overline x

b=\frac{r*s_y}{s_x}

We are given that \overline y=75, s_y=8, \overline x=280, s_x=30, and r=0.60, therefore our slope, b, is:

b=\frac{r*s_y}{s_x}

b=\frac{(0.60)(8)}{30}

b=0.16

Therefore, the slope of the regression line is 0.16, which can be used along with the values of \overline y and \overline x to find the constant a:

a=\overline y-b \overline x

a=75-(0.16)(280)

a=30.2

This means our final regression line is \hat y = 30.2 + 0.16x

<u>Problem 5:</u>

The slope, b=0.16, means that for every 1 point earned for a student's pre-exam total, their final exam score will increase by 0.16 points for each point they earned on the pre-exam.

<u>Problem 6:</u>

The y-intercept (or constant), a=30.2, means that if a student's pre-exam total were 0, then they would expect to get a 30.2 on the final exam.

<u>Problem 7:</u>

R^{2}=(0.60)^{2}=0.36=36\%

<u>Problem 8:</u>

The fraction of variability (aka. coefficient of determination), R^2, means that a certain proportion (or percentage) of the variance in the response variable can be explained by the explanatory variable. In context, this means that 36% of the variance in final exam scores can be explained by the pre-exam scores.

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