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Mathematics

1 answer:

Irina-Kira [14]3 years ago

7 0

It's a linear program; the extrema will be at the corners.

Let's enumerate them. 4 choose 2 gives 6 possible meets of 4 lines. One pair are parallel, down to five to try.

4x-y=1 intersects x=0 at y=-1, outside the domain y≥0.

4x-y=1 intersects y=0 at x=1/4, (1/4, 0)

4x-y=1 intersects x=5 at y=19, (5,19)

(0,0) is outside the domain 4(0)-0=0 which isn't ≥1.

(5,0) is a valid corner.

It's a triangular domain. Three points to try,

C(1/4,0) = 6(1/4) + 2(0) = 3/2

C(5,19) = 6(5) + 2(19) = 68

C(5,0) = 6(5) + 2(0) = 30

Answer: Maximum C=68 at (x,y)=(5,19)

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First, we can solve the direct product:

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Now we will use the property:

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Answer:

c. A and C

Step-by-step explanation:

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Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=100, p=0.11)$