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Mark brainliest please
43.305 or in Mixed Number is 43 61/200 or in improper Fraction is 8661/200
Answer:
1 and -7
Step-by-step explanation:
Answer:
Part 1) Option D. must be an acute angle
Part 2) m∠A=70°
Step-by-step explanation:
Part 1) In triangle ABC, if an exterior angle drawn at vertex C measures 45, then angle B...
we know that
An exterior angle of a triangle is equal to the sum of the opposite interior angles
so
The measure of an exterior angle at C is equal to the sum of the interior angles at A and B
we have that
45°=m∠A+m∠B
therefore
m∠B < 90°
Angle B must be an acute angle
Part 2)
we know that
An exterior angle of a triangle is equal to the sum of the opposite interior angles
so
The measure of an exterior angle at B is equal to the sum of the interior angles at A and C
m∠A+m∠C=2m∠C+5
m∠C=m∠A-5 ----> equation A
m∠C=65° ----> equation B
substitute equation B in equation A
65°=m∠A-5
m∠A=(65+5)°=70°
We analyze the chart and observe that the linear function is

, since this relation holds for all values in the table. Drawing this line over the quadratic function shows that they intersect
twice, at
both the positive and negative x-coordinates.This is by far the easiest way to solve this problem, but if you're interested in learning how to do it algebraically, read on! To prove this more rigorously, we can find that the equation of the parabola is
Substituting in

, we find that
the intersection points occur where 
, or

or

This equation doesn't factor nicely, so we use the
quadratic formula to learn that

Hence, the x-coordinates of the intersection points are

, which is
positive, and

, which is
negative. This proves that there are intersection points on both ends of the axis.