You can using any equation you want to solve for one of the variables. For instance, if you want to solve for x you turn one of the equations so y is by its self
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2x + 3y = 5
4x - y =3
I am going to use </span>4x - y =3
-y = -4x + 3
y = 4x -3
Now you can substitute 4x - 3 for y in 2x + 3y = 5 and solve for x
2x + 3y = 5
2x + 3(4x - 3) = 5
Can’t see the question clearly
Since this is a right triangle, we can use our trigonometric functions to solve for x.
Since we know the adjacent side and hypotenuse, we will use cosine.
Based on the function

, we can solve for x. The adjacent side is 7 and the hypotenuse is 12. Plugging this in, we get

.
Now, we must use our inverse trigonometric functions to solve for x:

The inverse cosine and cosine on the left side cancel, leaving you with:
(-2y + 5 ) ( y+3)
= -2y^2 -6y +5y +15
= -2y^2 - y +15
the answer is B