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Anna71 [15]
3 years ago
13

The function f(x) = is translated up 4 units. Which equation represents the translated function?

Mathematics
2 answers:
r-ruslan [8.4K]3 years ago
5 0

Answer:

f(x)= is translated up four units can be written as

f(x)+4

Step-by-step explanation:

kkurt [141]3 years ago
3 0

Answer:

The translated function can be written as:

y = f(x) + 4

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A regression analysis between sales (y in $1000) and advertising (x in dollars) resulted in the following equation y = 50,000 +
Vikentia [17]

Answer:

D. increase of $1 in advertising is associated with an increase of $6,000 in sales.

Step-by-step explanation:

Every dollar in advertisting is multiply by 6 in the equation, but every unit in y represent $1000. That means that $1 1n advertisting is multiply by 6 and then by $1000, that is $1 in advertisting = $6000 in sales.

4 0
3 years ago
For the function y=3x2: (a) Find the average rate of change of y with respect to x over the interval [3,6]. (b) Find the instant
nirvana33 [79]

Answer:

The instantaneous rate of change of y with respect to x at the value x = 3 is 18.

Step-by-step explanation:

a) Geometrically speaking, the average rate of change of y with respect to x over the interval by definition of secant line:

r = \frac{y(b) -y(a)}{b-a} (1)

Where:

a, b - Lower and upper bounds of the interval.

y(a), y(b) - Function exaluated at lower and upper bounds of the interval.

If we know that y = 3\cdot x^{2}, a = 3 and b = 6, then the average rate of change of y with respect to x over the interval is:

r = \frac{3\cdot (6)^{2}-3\cdot (3)^{2}}{6-3}

r = 27

The average rate of change of y with respect to x over the interval [3,6] is 27.

b) The instantaneous rate of change can be determined by the following definition:

y' =  \lim_{h \to 0}\frac{y(x+h)-y(x)}{h} (2)

Where:

h - Change rate.

y(x), y(x+h) - Function evaluated at x and x+h.

If we know that x = 3 and y = 3\cdot x^{2}, then the instantaneous rate of change of y with respect to x is:

y' =  \lim_{h \to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}

y' =  3\cdot \lim_{h \to 0} \frac{(x+h)^{2}-x^{2}}{h}

y' = 3\cdot  \lim_{h \to 0} \frac{2\cdot h\cdot x +h^{2}}{h}

y' = 6\cdot  \lim_{h \to 0} x +3\cdot  \lim_{h \to 0} h

y' = 6\cdot x

y' = 6\cdot (3)

y' = 18

The instantaneous rate of change of y with respect to x at the value x = 3 is 18.

5 0
3 years ago
I need help with number 18
algol13

Answer:

61.6666666667 =61.67

Step-by-step explanation:

4 0
3 years ago
30 ounces at $4.00 per pound. how much was paid for 30 ounces
Nata [24]
It would be $7.50 because 4 ounces equals $1 so 30/4 =7.5
3 0
3 years ago
А
Tpy6a [65]

Answer:

angle abc=125°

.......................

6 0
3 years ago
Read 2 more answers
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