Factor out the 4 in both equations
8a^2-20^2=(2^2 times a^2 times 2)-(2^2 times 5)
therefor it is also equal to
(2a)^2 times 2-(2^2 times 5)
we can force it into a difference of 2 perfect squares which is a^2-b^2=(a-b)(a+b)
(2a√2)^2-(2√5)^2=((2a√2)-(2√5))((2a√2)+(2√5))
Answer:
144 rupees
Step-by-step explanation:
2 kg= 24 rupees
2/2 kg= 24/2 rupees
1 kg= 12 rupees
1×12 kg= 12×12 rupees
12 kg= 144 rupees
The composition of 2 functions is B
Given:
The system of equations is:
Line A: 
Line B: 
To find:
The solution of given system of equations.
Solution:
We have,
...(i)
...(ii)
Equating (i) and (ii), we get



Divide both sides by 2.

Substituting
in (i), we get
The solution of system of equations is (-4,-8).
Now verify the solution by substituting
in the given equations.


This statement is true.
Similarly,



This statement is also true.
Therefore, (-4,-8) is a solution of the given system of equations, because the point satisfies both equations. Hence, the correct option is C.
D. cause you gotta isolate your variables (the cereal boxes) then get rid of the coefficent (2)