Kim is x years old . jordan is 7 year older than kim. four times jordans age is equal to 200

2 answers:

6 0

So we don't know how old Kim is.
Jordan is 7 years older, and 4x of Jordan's age equals to 200.

So Jordan is 50 because 50 x 4 = 200.
Back to Kim, 50 - 7 = 43. Kim is 43.

Now, you write the equation. I helped you alot.

Svet_ta [14]3 years ago

3 0

Kim is x
Jordan is x+7
Jordan x 4 = 200

Therefore 4(x+7) = 200
X+7 = 50
X = 43

Kim is 43, Jordan is 50.

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Can someone please help me?<br> If g(x) = x2 - 5x + 2, find g(0).

Debora [2.8K]

g(x) = x² - 5x + 2

You are looking for g(0). This means that you must replace all the x values in the equation above with 0

(0)² - 5(0) + 2

Now you need to solve according to the rules of PEMDAS:

(0)² - 5(0) + 2

0 - 5(0) + 2

0 - 0 + 2

0 + 2

g(0) = 2

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5 0

3 years ago

If sin A = 3/8, find the value of cosec A - sec A.

alexira [117]

Answer:

$\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}$

Step by step explanation:

$\text{Given that,}\\\\~~~~~~\sin A = \dfrac 38 \\\\\implies \sin^2 A = \dfrac 9{64}\\\\\implies 1 - \cos^2 A = \dfrac{9}{64}\\\\\implies \cos ^2 A = 1 - \dfrac 9{64}\\\\\implies \cos^2 A = \dfrac{55}{64}\\\\\implies \cos A =\pm\sqrt{\dfrac{55}{64}}\\ \\\implies \cos A = \pm\dfrac{\sqrt{55}}8\\\\$

$\implies \dfrac 1{\cos A} = \pm\dfrac{8}{\sqrt{55}}$

$\text{Now,}\\\\\csc A - \sec A\\\\=\dfrac{1}{\sin A}- \dfrac{1}{\cos A}\\\\=\dfrac 83 -\left(\pm \dfrac 8{\sqrt {55}} \right)\\ \\\text{Hence,}\\\\\csc A - \sec A = \dfrac 83 + \dfrac{8}{\sqrt{55}}\\\\\csc A - \sec A = \dfrac 83 - \dfrac{8}{\sqrt{55}}$