Answer:
88
Step-by-step explanation:
Write the expression for the sum in the relation you want.
Sn = u1(r^n -1)/(r -1) = 2.1(1.06^n -1)/(1.06 -1)
Sn = (2.1/0.06)(1.06^n -1) = 35(1.06^n -1)
The relation we want is ...
Sn > 5543
35(1.06^n -1) > 5543 . . . . substitute for Sn
1.06^n -1 > 5543/35 . . . . divide by 35
1.06^n > 5578/35 . . . . . . add 1
n·log(1.06) > log(5578/35) . . . take the log
n > 87.03 . . . . . . . . . . . . . . divide by the coefficient of n
The least value of n such that Sn > 5543 is 88.
Store one since the 15% is take off 90 dollars which makes it 510
Answer:
Alex's ride is $15.25
The equation to find this is
1.25m + 4 = cost
m = miles traveled
Let x,x+2,x+4,x+6 be 4 consecutive no then,
sum of first 3 no=4x+12
According to condition,
20 less than 5 times 4th= 4 more than sum of 1st,2nd and 3rd
5(x+6)-20=4+(sum of first 3 no)
5(x+6)-20=4+(4x+12)
5(x+6)-20=4x+16
5x+30-20=4x+16
5x+10=4x+16
5x-4x=16-10
x=6
So,
1st no=x=6
2nd no=x+2=8
3rd no=x+4=6+4=10
4th no=x+6=6+6=12