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miskamm [114]
2 years ago
14

A college graduate expects to earn a salary of 60000 during the first year after graduation and receive a 4% raise every year af

ter that what is the total income he will have received after ten years?

Mathematics
2 answers:
guapka [62]2 years ago
6 0

So, there is an exponential growth formula you use.

First, write the initial cost which is

60,000

Then write 1+ the percentage of growth rate which is 0.04 percent. Then, right the time as an exponent after certain amount of years.

60,000(1+0.04)^10

60,000(1.04)^10

Plug this in a calculator

it should be 88814.6571

I hope this helps.

Butoxors [25]2 years ago
3 0

Answer:

88814.66 dollars

Step-by-step explanation:

Given that a college graduate expects to earn a salary of 60000 during the first year after graduation and receive a 4% raise every year

Hence have

Salary after t years = S(t) = 60000(1+4%)^t

Here t= 10

S(10) =60000(1.04)^10 = 88814.66 dollars

Thus we have after 10 years the revenue would be 88814.66 dollars

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if we have a geometric series with u1 = 2.1 and r= 1.06, what would the least value of n be such that Sn > 5543?
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Answer:

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Step-by-step explanation:

Write the expression for the sum in the relation you want.

  Sn = u1(r^n -1)/(r -1) = 2.1(1.06^n -1)/(1.06 -1)

  Sn = (2.1/0.06)(1.06^n -1) = 35(1.06^n -1)

The relation we want is ...

  Sn > 5543

  35(1.06^n -1) > 5543 . . . . substitute for Sn

  1.06^n -1 > 5543/35 . . . .  divide by 35

  1.06^n > 5578/35 . . . . . . add 1

  n·log(1.06) > log(5578/35) . . . take the log

  n > 87.03 . . . . . . . . . . . . . . divide by the coefficient of n

The least value of n such that Sn > 5543 is 88.

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50 POINTS FOR THIS ALGEBRA WORD PROBLEM
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Let x,x+2,x+4,x+6 be 4 consecutive no then,

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According to condition,

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