The 8th term of the geometric sequence is 13122x^22
<h3>Explicit form of a geometric sequence</h3>
The explicit form of a geometric sequence is expressed according to the equation;
Tn = ar^n-1
where
r is the common ratio
a is the first term
n is the number of terms
Given the sequence below;
6x,18x^4,54x^7
r = 18x^4/6x
r = 3x^3
a = 6x
n = 8
Substitute to have:
T8 = 6x(3x^3)^8-1
T8 = 6x (3x^3)^7
T8 = 13122x^22
Hence the 8th term of the geometric sequence is 13122x^22
Learn more on geometric sequence here: brainly.com/question/24643676
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Answer:
I’m sorry but I’m not much help. I usually don’t answer questions I don’t know about, but I can do one thing.
My other answer was was lacking (I also believe I should have furthermore edited it.), therefore I will attempt to explain the steps correctly this time. I don't know what exactly is requested nor what you are learning, but I suspect it would be combinations, factorials, and/or permutations, something along those lines. Firstly I figured out my answer using factorials.
FROM: F,R,O,M. This obtains 4 letters.
4! (1 x 2 x 3 x 4)= 24
I am unsure if this is what you are looking for though. I hope this helped a bit.
Gradient = 5
9 = 5 + c
C = 4
Answer:
Y=5x+4
