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castortr0y [4]
3 years ago
7

When an object with a momentum of 80 kg ´ m/s collides with an object with a momentum of –100 kg ´ m/s the total momentum after

the collision is ______.
a.
20 kg x m/s
c.
20 kg x m/s2
b.
-20 kg x m/s
d.
-20 kg x m/s2
Mathematics
1 answer:
mojhsa [17]3 years ago
3 0
This is a physics problem.

The law is that the momentum is preserved: total momentum before collsion = total momentum after collision

Momentum before collision = 80 kg.m/s - 100 kg.m/s = -20 kg.m/s

Then answer is b. - 20 kg.m/s
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Sin^2 a/2 - sin a/2 + 1/4 = 0​
zimovet [89]

Answer:

<u>a = 60° or π/3</u>

Step-by-step explanation:

<u>Given :-</u>

sin² a/2 - sin a/2 + 1/4

<u>To find :-</u>

a

<u>Solving :-</u>

sin² a/2 - sin a/2 + 1/4 = (sin a/2 - 1/2)² = 0

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<u>Solution :-</u>

<u>a = 60° or π/3</u>

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2 years ago
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Eva8 [605]

Answer:

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Step-by-step explanation:

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The area of the triangle is given by the  formula:

A_T=\frac{bh}{2}

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A_T=\frac{(4cm)(5cm)}{2}\\ \\A_T=\frac{20cm^2}{2} \\\\A_T=10cm^2

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3 0
3 years ago
Read 2 more answers
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Genrish500 [490]

Answer:

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3 years ago
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