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3 years ago

9. In a 25-kilometer triathlon, competitors sim 2 kilometers, run 5 kilometers, and bike the rest

Mathematics

1 answer:

postnew [5]3 years ago

8 0

Answer:

They bike 18 kilometers

Step-by-step explanation:

25-2+5=18

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What is the length of line segment AB? 1 inch v3 inches 4 inches 475 inches

drek231 [11]

Answer:

$AB=\sqrt{3}\ in$

Step-by-step explanation:

The correct question is

The diagonal of rectangle ABCD measures 2 inches in length.

What is the length of line segment AB?

The picture of the question in the attached figure

we know that

In the right triangle ABD

$cos(30^o)=\frac{AB}{BD}$ ----> by CAH (adjacent side divided by the hypotenuse)

substitute the given values

$cos(30^o)=\frac{AB}{2}$

Remember that

$cos(30^o)=\frac{\sqrt{3}}{2}$

$\frac{AB}{2}=\frac{\sqrt{3}}{2}$

$AB=\sqrt{3}\ in$

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3 years ago

PLEASE HELP ME!! I need this answered right now

Flauer [41]

I will be C because 120 + 36+x= 180
156-180=24

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3 years ago

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The triangle shown in the diagram is going to be dilated by a scale factor of 1 3 . What is the length of the new side that corr

Rufina [12.5K]

What’s is side AB if I don’t have that I don’t know how to figure out how they correspond

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3 years ago

* E Which angle is an acute angle?

vodomira [7]

Answer:

angle COD is right answer

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3 years ago

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Please select the best answer from the choices provided

Ira Lisetskai [31]

Answer:

The correct answer option is c. $\frac{1}{9a^2}$ .

Step-by-step explanation:

We are given an expression $(27a^{-3})^{-\frac{2}{3} }$ and we are supposed to simplify it.

We can also write $(27a^{-3})^{-\frac{2}{3} }$ as $(\frac{3^3}{a^3} )^{-\frac{2}{3} }$ .

We know the power rule (a^m)^n=a^{mn} which means that to raise a power to a power you need to multiply the exponents.

So multiplying the exponents to get:

$\frac{3^{(3.-\frac{2}{3})} }{a^{(3.\frac{2}{3})} }\\\\\frac{3^{-2}}{a^2}\\ \\\frac{1}{3^2a^2} \\\\\frac{1}{9a^2}$

Therefore, the correct answer option is c. $\frac{1}{9a^2}$ .

4 0

3 years ago