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stiv31 [10]
3 years ago
9

Pls. Help me to solve this math problem.

Mathematics
1 answer:
Tju [1.3M]3 years ago
4 0

\bf (\stackrel{x_1}{x}~,~\stackrel{y_1}{-7})\qquad (\stackrel{x_2}{-6}~,~\stackrel{y_2}{8}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{8-(-7)}{-6-x}=\stackrel{\textit{slope}}{-\cfrac{15}{7}}\implies \cfrac{8+7}{-6-x}=-\cfrac{15}{7} \\\\\\ \cfrac{15}{-6-x}=-\cfrac{15}{7}\implies 105=(-6-x)(-15)\implies 105=90+15x \\\\\\ 15=15x\implies \cfrac{15}{15}=x\implies 1=x

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Two gears in a machine are aligned by a mark drawn from the center of one gear to the center of the other. If the first gear has
Aleksandr [31]

Answer:

5

Step-by-step explanation:

for the first gear

revolutions/teeth

1 / 24

2 / 48

3 / 72

4 / 96

5 / 120

6 / 144

for the second gear

revolutions/teeth

1 / 40

2 / 80

3 / 120

4 / 160

<em>the two marks will meet after 120 teeth, 5 revolutions of the first gear and 3 revolutions of the second.</em>

the way to get that amount of teeth is

24 = 2 \times 2 \times 2 \times 3 =  {2}^{3}  \times 3

40 = 2 \times 2 \times 2 \times 5 =   {2}^{3}  \times 5

the Least Common Multiple equals the product of all factors, but those factors who are repeted for both numbers should be only once.

{2}^{3} \times 5 \times 3 = 120

120 teeth are 5 revolutions for gear1 and 3 por gear2

8 0
3 years ago
If AB = 2x–8 and AC = x+9, What is the length of BC?
Virty [35]

Answer:

17

Step-by-step explanation:

2x-8=x+9

x=17

4 0
3 years ago
Read 2 more answers
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maksim [4K]

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7 0
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vladimir1956 [14]

The domain is the input values, which would also be X values.

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Diego was trying to write 2^3 · 2^2 with a single exponent and wrote 2^3·2^2 = 2^3*2 = 2^6 . Explain to Diego what his mistake w
cupoosta [38]

Answer:

2^3·2^2 = 2^3+2 = 2^5  

Step-by-step explanation:

Diego was trying to write 2^3 · 2^2

He wrote  2^3·2^2 = 2^3*2 = 2^6  

But this is wrong because when bases are same exponents are added.

This is the law of exponents.

The correct form would be

2^3·2^2 = 2^3+2 = 2^5  

For understanding it better we can write it like this

2^3·2^2 =

There are 3 two and 2 twos .When totaled there are 5 two not 6 twos.

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3 years ago
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