<span>V/7= 22
Multiply 7 on both sides
Final Answer: V = 154</span>
Answer:
y = 23
x = -4.5
Step-by-step explanation:
Given:
Equation
8x + y = -13 ......eq1
8x + 2y = 10........eq2
Find:
Solution
Computation:
Eq2 - Eq1
y = 23
From eq1
8x + y = -13
8x + 23 = -13
8x = -36
x = -4.5
Answer:
19 6j/5
Step-by-step explanation:
Answer:
-23
Step-by-step explanation:
rearrange to point slope form first
slope can be fine by y2-y1/x2-x1 (im using the first 2 points)
so 13-25 = -12 and -54-(-72) = 18, and the slope is -12/18 which is -2/3
then you can use any point (i used the first point) to create the point slope form which is y-ypoint=slope(x-xpoint) and equation would be y-25=-2/3(x+72)
turn it into slope intercept form by multiplying -2/3 within the equation and adding -25 on both sides
you will get y= -2/3x-23
and the y intercept will be (0, -23)
Answer:
4y = 6x + 40
Step-by-step explanation:
The general equation of a straight line is y = mx + b
m is the slope and b is the y-intercept
let us write both equations in this form;
we have this as;
6y = -4x + 1
y = -4x/6 + 1/6
and;
2x + 3y = 18
3y = -2x + 18
y = -2x/3 + 6
So firstly we want to find an equation that is perpendicular to the first
When two lines are perpendicular, their slopes has a product of -1
The slope of the first line is -4/6
let the slope of the line we want be m
As per they are perpendicular;
-4/6 * m = -1
-4m/6 = -1
-4m = -6
m = 6/4
So now, we want the y-intercept greater than that of the second equation which is a y-intercept of 6
we can choose 10
and we have the equation as:
y = 6x/4 + 10
multiply through by 4
4y = 6x + 40
