Answer:
The confidence interval for the proportion of students supporting the fee increase
( 0.77024, 0.81776)
Step-by-step explanation:
<u>Explanation:</u>
Given data a survey of an urban university (population of 25,450) showed that 883 of 1,112 students sampled supported a fee increase to fund improvements to the student recreation center.
Given sample size 'n' = 1112
Sample proportion 'p' = 
q = 1 - p = 1- 0.7940 = 0.206
<u>The 95% level of confidence intervals</u>
The confidence interval for the proportion of students supporting the fee increase
The Z-score at 95% level of significance =1.96
(0.7940-0.02376 , 0.7940+0.02376)
( 0.77024, 0.81776)
<u>Conclusion:</u>-
The confidence interval for the proportion of students supporting the fee increase
( 0.77024, 0.81776)
Answer: 5.99
Step-by-step explanation:
Ling spent $23.96 on cooking fuel for an upcoming camping trip.
Total number of cans of cooking fuel bought = 4
So, the cost of each can = dollars
Hence, Ling paid $5.99 for each can of cooking fuel.
Answer: 18
Step-by-step explanation:
The formula to find the minimum sample size is given by :_
, where 
= population standard deviation.
z*= critical z-value.
E= Margin of error.
Given : 
E= ± 8
We know that critical value corresponding to 99% confidence level = z*=2.576 [Using z-table]
Then, the required sample size would be :
[Round to next integer.]
Hence, the required minimum sample size = 18
32. For every one salad it was 8 steaks, so if they sold 4 steaks, just multiply 4 by 8, where 8 represents the number of salads for every steak. The answer would be 32. Correct me if I'm wrong but that my answer.
