The jones family is landscaping their yard. Their yard is 160 square feet and one side is 10 feet long. What is the length of th
2 answers:
Answer:
16 feet is the answer.
Step-by-step explanation:
The area of the yard is given as = 160 square feet
One side is given as 10 feet.
The area of the rectangle is = length x width
Let the other side be = x
So,
= 16 feet
Hence, length is 16 feet and width is 10 feet.
Yes, they will have enough space as 3 bushes will need 3*4=12 feet space and the length is already 16 feet.
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Answer:
y = one-third x + 3
Step-by-step explanation:
Slope-Intercept Form: y = mx + b
Slope Formula:
Step 1: Find slope <em>m</em>
m = (4 - 1)/(3 + 6)
m = 3/9
m = 1/3
y = 1/3x + b
Step 2: Find <em>b</em>
4 = 1/3(3) + b
4 = 1 + b
b = 3
Step 3: Rewrite
y = 1/3x + 3
Answer:
The probability that randomly selected road will be at least 25.8 cm long will be 48%.
Step-by-step explanation:
Given: uniform distribution with min and max values of 18 and 33 respectively.
To find : probability density for upper cumulative frequency i.e 25.8 at least means x25.8 upto 33 cm i.e the maximum limit of function.
Solution:
we have by definition , of uniform distribution
we get , probability density function defines as :
<em>F(x,a,b)= </em><em> </em>
=1/(33-18)=1/15=0.0667.
this is probability density function.
here the x=25.8 , a=18 and b=33
for lower cumulative frequency it defines as ;
P(x,a,b)= =25.8-18/33-18=0.52
for upper cumulative frequency it defines as ;
Q(x,a,b)=b-x/b-a=33-25.8/33-18=0.48
here at least 25.8 cm probability means it should be greater than a value(18cm) hence it is provided by the upper cumulative frequency
i.e. Q(x,a,b)=0.48
The probability that randomly selected road will be at least 25.8 cm long will be 48%.
Answer:
15. 2
16. or 1.6875
17. or 0.5666666667
18. 5
19. or 4.375
20. or 4.4
Step-by-step explanation:
Find common denominators. Multiply then simplify (if possible).