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Lena [83]
3 years ago
14

Christian reads 14 book every 23 week. How many books does Christian read per week? ​ 16 ​ ​ 38 ​ ​ 223 ​ 6

Mathematics
1 answer:
Drupady [299]3 years ago
8 0

。☆✼★ ━━━━━━━━━━━━━━  ☾

Divide by 2 to get 1/3 of the week:

1/4 / 2 = 1/8

Multiply by 3 to get the full week:

1/8 x 3 = 3/8

Thus your answer is B. 3/8

Have A Nice Day ❤  

Stay Brainly! ヅ  

- Ally ✧  

。☆✼★ ━━━━━━━━━━━━━━  ☾

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“An architect is planning to incorporate several stone spheres of different sizes into the landscaping of a public park, and wor
Artist 52 [7]

Answer:

Part 1) The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Part 2) The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

Step-by-step explanation:

Step 1

Find the radius of each sphere

we know that

The circumference of a circle is equal to

C=2\pi r

<u><em>Find the radius of the sphere with a 5.50-meter circumference</em></u>

For C=5.50\ m

assume

\pi =3.14

substitute and solve for r

5.50=2(3.14)r

r=5.50/[2(3.14)]=0.88\ m

<u><em>Find the radius of the sphere with a 7.85-meter circumference</em></u>

For C=7.85\ m

assume

\pi =3.14

substitute and solve for r

7.85=2(3.14)r

r=7.85/[2(3.14)]=1.25\ m

step 2

Find the surface area of each sphere

The surface area of sphere is equal to

SA=4\pi r^{2}

<u><em>Find the surface area of sphere with a 5.50-meter circumference</em></u>

For r=0.88\ m

assume

\pi =3.14

substitute

SA=4(3.14)(0.88)^{2}

SA=9.73\ m^{2}

<u><em>Find the surface area of sphere with a 7.85-meter circumference</em></u>

For r=1.25\ m

assume

\pi =3.14

substitute

SA=4(3.14)(1.25)^{2}

SA=19.63\ m^{2}

step 3

Find the cost of finishing each sphere

we know that

To find out the cost , multiply the surface area by $92 per square meter

<u><em>Find the cost of sphere with a 5.50-meter circumference</em></u>

9.73*(92)=\$895.16

therefore

The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

<u><em>Find the cost of sphere with a 7.85-meter circumference</em></u>

19.63*(92)=\$1,805.96

therefore

The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

6 0
3 years ago
ASAP HW HELP. what’s the answer please I don’t understand!!
irakobra [83]

Answer:

1/2+1.5

I think. I'm sorry if I'm wrong

Step-by-step explanation:

4 0
2 years ago
An unbiased coin is tossed 20 times find the probability that the coin lands heads exactly 11 times
alexgriva [62]
Both the heads and tails will have a probability of 0.5 with a fair coin. ... TO find probability that foe the 7th toss head appears exactly 4 times.
7 0
3 years ago
6.
Ilia_Sergeevich [38]

Answer:

  • A. 5 to the power of negative 5 over 6

Step-by-step explanation:

  • \sqrt[3]{5} \sqrt{5} /\sqrt[3]{5^5} =
  • 5^{1/3+1/2-5/3}=
  • 5^{1/2-4/3}=
  • 5^{3/6-8/6}=
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6 0
2 years ago
I NEED HELP PLZ ( WILL GIVE BRAINLYIST) ( NO LINKS)
AlladinOne [14]

9514 1404 393

Answer:

  66 cm²

Step-by-step explanation:

The area of the polygon is the sum of the areas of the triangle and the rectangle it sits on. The dimensions of the triangle can be found by examining the top/bottom dimensions shown and the left/right dimensions shown.

The width (base) of the triangle is the difference between the lengths of the bottom and top horizontal lines: (12 -9) cm = 3 cm.

The height of the triangle is the difference between the lengths of the left and right sides of the figure: (9 -5) cm = 4 cm.

The dimensions of the rectangle are shown a the bottom and the left sides of the figure.

  triangle area = 1/2bh = 1/2(3 cm)(4 cm) = 6 cm²

  rectangle area = LW = (12 cm)(5 cm) = 60 cm²

Total polygon area = 6 cm² + 60 cm² = 66 cm²

4 0
3 years ago
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