Question

PLEASE HELPPP ANYONE Is the solution shown below correct? Explain. 9x+2=8x2+6x

Answer 1

we know that

The formula to solve a quadratic equation of the form $ax^{2}+bx+c=0$ is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}}{2a}$

In this problem we have

$-8x^{2}+3x+2=0$

so

$a=-8\\b=3\\c=2$

substitute in the formula  

$x=\frac{-3(+/-)\sqrt{3^{2}-4(-8)(2)}}{2(-8)}$

$x=\frac{-3(+/-)\sqrt{9+64}}{-16}$

$x=\frac{-3(+/-)\sqrt{73}}{-16}$

$x1=\frac{-3+\sqrt{73}}{-16}=\frac{3-\sqrt{73}}{16}$

$x2=\frac{-3-\sqrt{73}}{-16}=\frac{3+\sqrt{73}}{16}$

therefore

the answer is

The solution is not correct, there is a sign error under the radical. The radicand should be $73$

Answer 2

Answer:

Sample response from Edge

Step-by-step explanation:

No. The correct values of a, b, and c were substituted in, but the formula was simplified wrong. The 64 should be added so the radicand is 73. There should be 2 real roots.