Answer:
a-bi
Step-by-step explanation:
If a quadratic equation lx^2+mx+n=0 has one imaginary root as a+bi then the other root is the conjugate of a+bi = a-bi
Because we have l, m and n are real numbers and they are the coefficients.
Sum of roots = a+bi + second root = -m/l
When -m/l is real because the ratio of two real numbers, left side also has to be real.
Since bi is one imaginary term already there other root should have -bi in it so that the sum becomes real.
i.e. other root will be of the form c-bi for some real c.
Now product of roots = (a+bi)(c-bi) = n/l
Since right side is real, left side also must be real.
i.e.imaginary part =0
bi(a-c) =0
Or a =c
i.e. other root c-bi = a-bi
Hence proved.
Turn 7/4 into a decimal by dividing it and then multiply from there and you get 1.75. Then you time 5.4 by 1.75 and you get 9.45
Answer:
Step-by-step explanation:
B is correct: We Divide it (the coefficient b) by 2 and square the result.
Answer:
2/8
Step-by-step explanation:
I think this is subtraction (if not just tell me i'll edit)
6/8 - 2/4 = 6/8 - 4/8 = 2/8
Answer:
Step-by-step explanation:
did you get the answer