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wolverine [178]
3 years ago
14

Round to the nearest cent. $138.7836 from the hundreds place

Mathematics
2 answers:
mr_godi [17]3 years ago
8 0

$138.78 is the rounded figure

FinnZ [79.3K]3 years ago
8 0

$138.7836

One cent is one hundredth of a dollar, so you need to round to the nearest hundredth.

Starting from the left, keep all digits up to the hundredths.

$138.78

Since the digit to the right of the hundredths place is a 3, the 8 remains as an 8, and you're done.

Answer: $138.78

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Calculate the sample variance and sample standard deviation for the following frequency distribution of heights in centimeters f
Zolol [24]

Answer:

\bar X = \frac{\sum_{i=1}^n X_i f_i}{n}= \frac{22026.1}{171}=128.81

s^2 = \frac{2839948.85- \frac{(22026.1)^2}{171}}{171-1}= 16.59

s= \sqrt{16.587}=4.07

Step-by-step explanation:

For this case we can calculate the sample variance and deviation with the following table

Class               Midpoint (Xi)    fi        Xi*fi       Xi^2 *fi

120.6-123.6        122.1             17      2075.7   253443

123.7-126.7        125.2            49      6134.8    768077

126.8-129.8        128.3            29     3720.7    477365.8

129.9-132.9        131.4             41       5387.4   707904.4

133.0-136.0        134.5            35      4007.5   633158.8

___________________________________________

Total                                        171   22026.1    2839948.85

For this case we can calculate the mean or expected value with the following formula:

\bar X = \frac{\sum_{i=1}^n X_i f_i}{n}= \frac{22026.1}{171}=128.81

Now we can calculate the sample variance with the following formula:

s^2 =\frac{\sum f_i X^2_i -[\frac{(\sum X_i f_i)}{n}]^2}{n-1}

And if we replace we got:

s^2 = \frac{2839948.85- \frac{(22026.1)^2}{171}}{171-1}= 16.59

And the standard deviation would be the square root of the variance and we got:

s= \sqrt{16.59}=4.07

7 0
4 years ago
5 times a number increased by 4 is at least<br> nineteen
Anna35 [415]

Answer:

5(x+4) ≥ 19

x ≤  -1/5

Step-by-step explanation:

5(x+4) ≥ 19

5x + 20 ≥ 19

5x ≤  -1

x ≤  -1/5

5 0
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