Vic and Dan are 2, 897m apart.
<h3>How to determine the distance</h3>
It is important to note that the distance between Vic and Dan is the base of CN
Let's say the distance to Dan is x
The distance to Vic is y
Using cosine ratio, we have
cos α = opposite / adjacent
α = 72°
opposite = 553. 3cm
Adjacent = x
cos 72° = 
Cross multiply
× 
= 
m
The distance to Vic is y
Using the cosine ratio, we have
Cross multiply
m
To determine how far apart Vic and Dan, we use = x + y
= 1790. 61 + 1106. 6
= 2, 897. 21m
= 2, 897m
Thus, Vic and Dan are 2, 897m apart.
Learn more about bearing and distance here:
https://brainly.in/question/47782732
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Answer:
c
Step-by-step explanation:
segment BD has an "equidistant" distance and very similar to the distance between points C and E.
As we can see from the graph, point C is located between segment BD and point D is located in the middle of segment CE; and since the points are Equidistant (at the same distance), and both have a point in the middle, it can be deduced that their distances are equal or similar
Answer:25
Step-by-step explanation
5 x 5 = 25. Got this problem correct on Imagine Math.
Answer:
Step-by-step explanation:
Good evening ,
I guess it’s the C expression,
Because, C. 3n^2+n-2 so the coefficient of the term n is 1 and the coefficient of the term n^2 is 3
:)
Answer:
<em>Probability ≈ 0.0714</em>
Step-by-step explanation:
Consider permutation and combination;
