Answer:
30 mins
Step-by-step explanation:
<em>speed = distance/ time </em>
speed of car A
= 20/ 12 km/ min
= 5/ 3 km/ min
also, speed of car A = speed of car B
speed of car B = 5/ 3 km/ min = 50km / time taken (in mins)
=> t = 30 mins
You didn't include the table but I found this table for the same statement, so I will answer you based on the next table:
Runner distance time
Arabella 7,299 feet 561 seconds
Bettina 3,425 yards 13 minutes, 12 seconds
Chandra 8,214 feet 0,195 hours
Divya 1,62 miles 732 seconds
To answer the question you must find the rate for each runner and then calculate the time to run 3.1 miles at each rate.
First you need to convert the data to obtain the rate in miles per second.
These are the main conversion identities:
1 mile = 5280 feet
1 mile = 1760 yards
1 hour = 3600 seconds
1 hour = 60 minutes
1 minute = 60 seconds
Arabella:
rate: 7,229 feet / 561 seconds * (1 mile / 5280 feet) =
= 0.00244 mile/second
Time to run 3.1 miles: V = d / t => t = d / V = 3.1 miles / 0.00244 mile/second = 1270 seconds
Bettina:
13 minutes + 12 seconds = 13*60 seconds +12 seconds = 792 seconds
rate = 3425 yards / 792 seconds * 1 mile / 1760 yards = 0.00246 mile/seconds
Time to run 3.1 miles = 3.1 miles / 0.00246 mile/second = 1260 seconds
Chandra:
rate = 8214 feet / 0.195 hours * 1 mile / 5280 feet * 1hour / 3600 seconds =
= 0.00222 seconds
Time = 3.1 mile / 0.00222 seconds = 0.389 hour = 1396 seconds
Divya:
rate = 1.62 miles / 732 seconds = 0.00221 seconds
Time = 3.1 mile / 0.00221 seconds = 1403 seconds
Now you can find the difference between fhe last and the first 1403 seconds - 1260 seconds = 143 seconds
That is equivalent to 2.38 seconds.
Answer: The answer to the first is -29x-5. The Answer to the second is -5/6a - 5/8
Step-by-step explanation:I took the K12 test I hope this helps.
Answer:
B: Yes, his claim is reasonable because 90% is in the interval estimate.
Step-by-step explanation:
Height, weight, and income since they all deal with numbers
