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REY [17]
3 years ago
14

Determine whether the sequence is arithmetic or geometric.

Mathematics
1 answer:
Zarrin [17]3 years ago
6 0
S1.
32, 16, 0, -16, ...
It's an arithmetic sequence:
a_1=32;\ d=16-32=-16\\\\a_n=a_1+(n-1)d\\\\a_n=32+(n-1)\cdot(-16)=32-16n+16=48-16n

S2.
32, 16, 8, 4, ...
It's a geometric sequence:
a_1=32;\ r=16:32=\dfrac{1}{2}\\\\a_n=a_1r^{n-1}\\\\a_n=32\cdot\left(\dfrac{1}{2}\right)^{n-1}

Answer: sequence 1 is arithmetic and sequence 2 is geometric.
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2x+y=-9<br> -3x+11=y whathe is the answer
insens350 [35]
[ 2x + y = -9 ] x -3
[- 3x +11= y ] x 2

-6x -3y = 27
-6x + 22 = 2y

-6x +27 = 3y
-6x +22 = 2y

5 = y

-6x -3x5 = 27
-6x -15 = 27
-6x = 42
-x = 42/6
-x = 7
x = -7

answer

x = -7
y = 5




8 0
3 years ago
Solve: 16x2 - 80 = 0<br> Round the answer to the nearest hundredth.
GenaCL600 [577]

Answer:

-48

Step-by-step explanation:

16 x 2 = 32

32 - 80 = -48

5 0
3 years ago
Calculate the speed of a car that traveled 100 meters in 10 seconds. SHOW YOUR WORK AND INCLUDE UNITS.
Varvara68 [4.7K]

Answer:

12

Step-by-step explanation:

100;lol

8 0
2 years ago
in a game of poker, five players are each dealt 5 cards from a 52-card deck. how many ways are there to deal the cards?
Jlenok [28]

The number of ways to deal 5 cards to 5 players from a 52-card deck in a game of poker is (52!)/[(27!)*(5!)^5].

  • Permutations and combinations define nCr as ways of selecting 'r' number of items from 'n' items. 
  • nCr = (n!)/[r!(n-r)!]
  • here we want to deal 5 playing cards to each player.once we deal 5 playing cards to any participant,
  • the playing cards left inside the deck are reduced through five.
  • We deal a total of 25 playing cards, i.e., 5 playing cards to 5 gamers.
  • The number of ways to deal five playing cards to the primary participant is 52C5.The number of approaches to deal 5 playing cards to the second one participant is 47C5.
  • The wide variety of ways to deal 5 cards to the 0.33 player is 42C5.
  • The variety of methods to deal 5 cards to the fourth participant is 37C5.
  • The quantity of ways to deal 5 playing cards to the 5th player is 32C5.
  • the full quantity of methods is the general multiplication.
  • The total number of solutions = 52C5 * 47C5 * 42C5 * 37C5 * 32C5
  • When we simplify, we get (52!)/[(27!)*(5!)^5]. 

To learn more about permutation, visit :

brainly.com/question/1216161

#SPJ4

3 0
1 year ago
As shown in figure<br><img src="https://tex.z-dn.net/?f=5" id="TexFormula1" title="5" alt="5" align="absmiddle" class="latex-for
Ber [7]

Answer:

12. \sqrt{3}(2+\sqrt{6} )

13. 9√2

Step-by-step explanation:

12. 4√3-√12+√18

4√3-2√3+√18

2√3+√18

\sqrt{3}(2+\sqrt{6} )

13.(2√12-3√1/3)√6

(4√3 - 3√(1/3))√6

4√18 - 3√(6/3)

12√2-3√2

9√2

7 0
3 years ago
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