I= PRT
7280=26000×0.07T
7280\1820=1820T\1820
4=T
dats all
Answer:
24, -38, 62, -100
Step-by-step explanation:
The recursive formula is a_n = a_(n-2) - a_(n-1)
so. we try this 4 times after the -14 term
a_3 = -4 = 2 - 6 = a_1 - a_2
...
a_6 = a_4 - a_5 = 10 - (-14) = 24
a_7 = a_5 - a_6 = -14 - (24) = -38
a_8 = a_6 - a_7 = 24 - (-38) = 62
a_9 = a_7 - a_8 = -38 - 62 = -100
a_10 = a_8 - a_9 = 62 - (-100) = 162
Pick highest exponent of placeholder
that is the degree
x^2 and y^5
2<5
5>2
5th degree
Answer:
(x-2)^2
Step-by-step explanation:
The blue graph is shifted two units to the right of the "original" function x^2 (red). Let's recall the vertex form of a quadratic:
a (x-h)^2 + k
where a represents a constant that describes the opening of the parabola (up/down); h represents horizontal shift; and k represents vertical shift.
The blue graph is two units to the right (+2), there is NO vertical shift and NO change in how the parabola opens.
So, let's plug the appropriate values into vertex form:
(x-(+2))^2
= (x-2)^2
Number 4 is D and number 5 is A
