Ohms law = v= Ir
V= 0.02 x 4000 = 80v
Momentum = Mass × Velocity
= 61 × 8
= 488 kg m/s east
= 500 kg m/s east
Momentum is a vector quantity which means it has a direction as well as a numerical value (fancy word for this is magnitude). This means the final answer should also be in the direction "east".
Furthermore due to the significant figures in the question, the final answer should also be given to 1 sig fig (500) but if you don't want to then I imagine 488 is acceptable. (It's like this because we don't know how accurate we can be with the final answer from the numbers in the question.)
Explanation:
It is given that,
Height above which the stone was thrown, h = 10 m
Initial velocity of the stone, u = 8 m/s
Angle above the horizontal, 
The horizontal component of velocity is, 
The vertical component of velocity is, 
Let t is the time of flight in vertical motion. The second equation of motion is :
t = 0.34 seconds
Let s is the range of the stone. It can be calculated as :
s = 2.46 meters
So, the range of the stone is 2.46 meters. Hence, this is the required solution.
Answer:
6010.457N
Explanation:
Centripetal acceleration = a= V²/R
At a radius of 3.6m and velocity of 16.12m/s,
Acceleration is
a = 16.12²/ 3.6 = 72.182 m/s²
Force = Mass (m) * Acceleration (a)
36 = m * 72.182
m = 36/72.182
At breaking point
Radius = 0.468 m and Velocity = 75.1 m/s
a = V²/R = 75.1²/0.468
a = 12051.3 m/s
F = Mass(m) * Acceleration (a)
F = m * 12051.3
m = F/ 12051.3
Settings the ratio of mass equal
m = m
=> 36/72.182 = F/12051.3
F = 12051.3 * 36/72.182
F = 6010.457N
