A plane parallel to vectors <9, 6, 2> and <-8, -4, -5> is given by

Since the plane passes through point (5, -5, 8), then
-22(5) + 29(-5) + 12(8) = -110 - 145 + 96 = -159
The required plane is -22x + 29y + 12z = -159
z = 11/6x - 29/12y - 53/4
Answer:
D. is your answer
Step-by-step explanation:

Answer:3/2
Step-by-step explanation:
3/2
The solution to these linear equations is (4,-3)
So the x-value is 4
:)))