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Taya2010 [7]
3 years ago
8

Determine the equation of the plane in the form

Mathematics
1 answer:
Bond [772]3 years ago
8 0
A plane parallel to vectors <9, 6, 2> and <-8, -4, -5> is given by
\left|\begin{array}{ccc}x&y&z\\9&6&2\\-8&-4&-5\end{array}\right| =0\\ (-30 + 8)x - (-45 + 16)y + (-36 + 48)z = 0\\-22x+29y+12z=0

Since the plane passes through point (5, -5, 8), then
-22(5) + 29(-5) + 12(8) = -110 - 145 + 96 = -159

The required plane is -22x + 29y + 12z = -159
z = 11/6x - 29/12y - 53/4
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Answer:

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Step-by-step explanation:

we know that

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substitute in the formula

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Aleksandr [31]
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