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Taya2010 [7]
3 years ago
8

Determine the equation of the plane in the form

Mathematics
1 answer:
Bond [772]3 years ago
8 0
A plane parallel to vectors <9, 6, 2> and <-8, -4, -5> is given by
\left|\begin{array}{ccc}x&y&z\\9&6&2\\-8&-4&-5\end{array}\right| =0\\ (-30 + 8)x - (-45 + 16)y + (-36 + 48)z = 0\\-22x+29y+12z=0

Since the plane passes through point (5, -5, 8), then
-22(5) + 29(-5) + 12(8) = -110 - 145 + 96 = -159

The required plane is -22x + 29y + 12z = -159
z = 11/6x - 29/12y - 53/4
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In exponential form it is given as, 8⁻³ = $\frac{1}{512}

<u>Step-by-step explanation:</u>

We have to write the given equation in the exponential form, that is in the form of base to the power value.

Given:

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Here the base is 8.

In the exponential form, it is written as,

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Here the reciprocal of 512 is given, so,

base to the power -3 =   $\frac{1}{512}

So the exponential form is given as, 8⁻³ = $\frac{1}{512}

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Gekata [30.6K]

Answer: the second and the third one are right

Step-by-step explanation:

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vekshin1
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