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3 years ago

8

Determine the equation of the plane in the form

1 answer:

Bond [772]3 years ago

8 0

A plane parallel to vectors <9, 6, 2> and <-8, -4, -5> is given by
$\left|\begin{array}{ccc}x&y&z\\9&6&2\\-8&-4&-5\end{array}\right| =0\\ (-30 + 8)x - (-45 + 16)y + (-36 + 48)z = 0\\-22x+29y+12z=0$

Since the plane passes through point (5, -5, 8), then
-22(5) + 29(-5) + 12(8) = -110 - 145 + 96 = -159

The required plane is -22x + 29y + 12z = -159
z = 11/6x - 29/12y - 53/4

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Answer:

C. Probability is 0.90, which is inconsistent with the Empirical Rule.

Step-by-step explanation:

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$z=\frac{x-\mu}{\sigma}$

$z=\frac{107.5-97.5}{6.1}$

$z=\frac{10}{6.1}$

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$z\approx 1.64$

Now, we need to find the probability $P(-1.64$ .

Using property $P(a$ , we will get:

$P(-1.64$

From normal distribution table, we will get:

$P(-1.64$

$P(-1.64$

$P(-1.64$

Since the probability is 0.90, which is inconsistent with the Empirical Rule, therefore, option C is the correct choice.

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Step-by-step explanation:

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Step-by-step explanation:

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Okay!

Step-by-step explanation:

I have simplified the operation, and I got x^2 + 3.

If you wanted me to evaluate, the answer is still x^2 + 3.

If you wanted me to subtract then the answer is again, x^2 + 3.

Basically the answer is x^2 + 3.

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