You are an IT technician at your company. The company has two small offices in different cities. The company's head office conta
ins a DNS server and a DHCP server. The branch office does not contain a DHCP server. A user travels frequently between the head office and the branch office. You are configuring the IP address on this user's laptop. You must ensure that the user is able to connect to the Internet from both offices. How should you configure the Internet Protocol (TCP/IP) Properties dialog box on the user's laptop while expanding the least administrative effort?
1 answer:
The IT technician can configure DHCP and provide a static IP address a on the user’s computer.
Further explanation:
We have a case of one office containing a DHCP server and another one does not. A DHCP server assigns IPs to client machines and relies on DHCP protocol. By default, a DHCP server usually assigns clients in a network dynamic IPs. However, in this case scenario, since the head office contains a DHCP server, the IT technician is required to configure the general tab of the IPV4 network settings of the user’s machine to use the DHCP server. Configuring DHCP on client’s machine will ensure that the user will gain access to the network’s resources every time he is in head office.
A machine is built to check for alternate IP addresses if a DHCP server is absent. Therefore, to ensure that this user is always connected, the technician should also configure static IPs in the alternate configuration tab of IPV4 settings so that he will be able to connect to the branch office. Note that the static IP should be configured within the IP range of the branch office and not of the DHCP server.
In conclusion, you should avoid configuring a static IP on both the general and the alternate configuration tab for the branch office network. Doing so will restrict the user from accessing an established network while at the head office. The same case goes to the head office. Therefore, the technician should configure DHCP's general tab to be used in head office and static IPs on the alternate configuration tab to be used in the branch office.
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Answer:
Explanation:
The following is written in Java. It continues asking the user for inputs until they enter a -1. Then it saves all the values into an array and calculates the number of values entered, the highest, and lowest, and prints all the variables to the screen. The code was tested and the output can be seen in the attached image below.
import java.util.ArrayList;
import java.util.Arrays;
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
int count = 0;
int highest, lowest;
ArrayList<Integer> myArr = new ArrayList<>();
while (true) {
System.out.println("Enter a number [0-10] or -1 to exit");
int num = in.nextInt();
if (num != -1) {
if ((num >= 0) && (num <= 10)) {
count+= 1;
myArr.add(num);
} else {
System.out.println("Wrong Value");
}
} else {
break;
}
}
if (myArr.size() > 3) {
highest = myArr.get(0);
lowest = myArr.get(0);
for (int x: myArr) {
if (x > highest) {
highest = x;
}
if (x < lowest) {
lowest = x;
}
}
System.out.println("Number of Elements: " + count);
System.out.println("Highest: " + highest);
System.out.println("Lowest : " + lowest);
} else {
System.out.println("Number of Elements: " + count);
System.out.println("No Highest or Lowest Elements");
}
}
}
