<span>void printArray(int a[ ]) {
</span> int i; <span>for (i = 0; i < a.length; i++){
</span> <span>System.out.print(a[i]);
</span> System.out.println(); <span>}
</span> }
Answer:
The electronic scheduling tool can help you set an alarm as a reminder for different events, grouping them in other of dates, time, location and the concept of occasion if you need to pick anything along.
The paper calendar cannot do all this, just for you to check manually.
Explanation:
Electronic scheduling is fast, accurate and more organized, paper calendar is manual and less convenient to access.
Complete Question:
Determine the number of cache sets (S), tag bits (t), set index bits (s), and block offset bits (b) for a 4096-byte cache using 32-bit memory addresses, 8-byte cache blocks and a 8-way associative design. The cache has :
Cache size = 1024 bytes, sets t = 26.8, tag bits, s = 3.2, set index bit =2
Answer:
Check below for explanations
Explanation:
Cache size = 4096 bytes = 2¹² bytes
Memory address bit = 32
Block size = 8 bytes = 2³ bytes
Cache line = (cache size)/(Block size)
Cache line = 
Cache line = 2⁹
Block offset = 3 (From 2³)
Tag = (Memory address bit - block offset - Cache line bit)
Tag = (32 - 3 - 9)
Tag = 20
Total number of sets = 2⁹ = 512