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4 years ago

Vito uses 9 L of water to water 24 flowerpots he is wondering how many liters of water it would take to water 40 flowerpots

Mathematics

2 answers:

Elenna [48]4 years ago

8 0

Using ratios, 9 : 24
Find ? : 40

Solving Steps-
40 / 24 = 1 2/3

1 2/3 • 9 = 15

ANSWER is 15 L

ivann1987 [24]4 years ago

5 0

Answer:15

Step-by-step explanation:

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PLZ HELP!!!!!! What is the equation of the line graphed below?

alex41 [277]

Answer:

Your answer is B

Step-by-step explanation:

First we have to find the Y intercept, which is -2.

Then you have to find the slope. Rise/Run

If you count up 5 and left 2 you get your next point. Meaning that 5/-2 is your slope.

6 0

3 years ago

Find the indicated side of the<br> right triangle.

Advocard [28]

Answer:

?=9

Step-by-step explanation:

We have a special right triangle, the 45-45-90 triangle.

In a 45-45-90 triangle, the side lengths are x, and the hypotenuse is x√2.

Since we know that the side length is 9, this means that:

$x=9\\\text{Hypotenuse}=x\sqrt2\\\text{Hypotenuse}=9\sqrt2$

The ? is 9.

8 0

3 years ago

The function d(s) = 0.0056s squared + 0.14s models the stopping distance

victus00 [196]

Answer:

The car must have a speed of 25 kilometres per hour to stop after moving 7 metres.

Step-by-step explanation:

Let be $d(s) = 0.0056\cdot s^{2} + 0.14\cdot s$ , where $d$ is the stopping distance measured in metres and $s$ is the speed measured in kilometres per hour. The second-order polynomial is drawn with the help of a graphing tool and whose outcome is presented below as attachment.

The procedure to find the speed related to the given stopping distance is described below:

1) Construct the graph of $d(s)$ .

2) Add the function $d = 7\,m$ .

3) The point of intersection between both curves contains the speed related to given stopping distance.

In consequence, the car must have a speed of 25 kilometres per hour to stop after moving 7 metres.

4 0

3 years ago

Evaluate the following integral using trigonometric substitution.

wariber [46]

Answer:

Step-by-step explanation:

1. Given the integral function $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ , using trigonometric substitution, the substitution that will be most helpful in this case is substituting x as $asin \theta$ i.e $x = a sin\theta$ .

All integrals in the form $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ are always evaluated using the substitute given where 'a' is any constant.

From the given integral, $\int\limits {7\sqrt{49-x^{2} } } \, dx = \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx$ where a = 7 in this case.

The substitute will therefore be $x = 7 sin\theta$

2.) Given $x = 7 sin\theta$

$\frac{dx}{d \theta} = 7cos \theta$

cross multiplying

$dx = 7cos\theta d\theta$

3.) Rewriting the given integral using the substiution will result into;

$\int\limits {7\sqrt{49-x^{2} } } \, dx \\= \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -(7sin\theta)^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -49sin^{2}\theta } } \, dx\\= \int\limits {7\sqrt{49(1-sin^{2}\theta)} } } \, dx\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, dx\\since\ dx = 7cos\theta d\theta\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, 7cos\theta d\theta\\= \int\limits {7\{7(cos\theta)} }}} \, 7cos\theta d\theta\\$