All categories

3 years ago

Multiply. Express your answer in simplest form.

Mathematics

2 answers:

Mariana [72]3 years ago

6 0

Answer:

14 2/3

Step-by-step explanation:

mixer [17]3 years ago

5 0

Answer:

14 $\frac{1}{4}$

Step-by-step explanation:

before multiplying change the mixed number to an improper fraction

7 $\frac{1}{8}$ = $\frac{57}{8}$

$\frac{57}{8}$ × 2

= $\frac{57(2)}{8}$ = $\frac{57}{4}$ = 14 $\frac{1}{4}$

You might be interested in

Drag the numbers to order them from least to greatest.

vekshin1

$\sqrt{7} = 2.6457\\\sqrt{17} = 4.1231\\\pi = 3.1415926$

Anwer

$\sqrt{7}$

2.8

$\pi$

$\sqrt{17}$

4.6

6 0

3 years ago

Read 2 more answers

The product of five rational numbers is positive. At most,

Yuliya22 [10]

It would be four. You can have four negative numbers and they will turn positive. For example, if you had -2 x -2 x -4 x -4 = 64. 64 would be positive because two negative numbers equal a positive number.

6 0

3 years ago

The heights of women in the USA are normally distributed with a mean of 64 inches and a standard deviation of 3 inches.

Rainbow [258]

Answer:

(a) 0.2061

(b) 0.2514

Step-by-step explanation:

Let <em>X</em> denote the heights of women in the USA.

It is provided that <em>X</em> follows a normal distribution with a mean of 64 inches and a standard deviation of 3 inches.

(a)

Compute the probability that the sample mean is greater than 63 inches as follows:

$P(\bar X>63)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{63-64}{3/\sqrt{6}})\\\\=P(Z>-0.82)\\\\=P(Z$

Thus, the probability that the sample mean is greater than 63 inches is 0.2061.

(b)

Compute the probability that a randomly selected woman is taller than 66 inches as follows:

$P(X>66)=P(\frac{X-\mu}{\sigma}>\frac{66-64}{3})\\\\=P(Z>0.67)\\\\=1-P(Z$

Thus, the probability that a randomly selected woman is taller than 66 inches is 0.2514.

(c)

Compute the probability that the mean height of a random sample of 100 women is greater than 66 inches as follows:

$P(\bar X>66)=P(\frac{\bar X-\mu}{\sigma/\sqrt{n}}>\frac{66-64}{3/\sqrt{100}})\\\\=P(Z>6.67)\\\\\ =0$

Thus, the probability that the mean height of a random sample of 100 women is greater than 66 inches is 0.

8 0

3 years ago

Please HELP!! PLEASE I BEG I WILL DO ANYTHING LITERALLY Create a scenario that demonstrates object permanence.

Eddi Din [679]

I had a very sweet dog, her name was Lilac. I had her for 13 years and unfortunately she passed away. This shows that no one object is permanent

7 0

3 years ago

Find the value of f(-3) for the function below. f(x) = 2x + 10 A. 16 B. -4 C. 4 D. -6.5

Free_Kalibri [48]

Answer: C. 4

Step-by-step explanation:

5 0

4 years ago