Answer:
prove that:
Sin²A/Cos²A + Cos²A/Sin²A = 1/Cos²A Sin²A - 2
LHS = \frac{Sin^2A}{Cos^2A} + \frac{Cos^2A}{Sin^2A}
Cos
2
A
Sin
2
A
+
Sin
2
A
Cos
2
A
= \begin{lgathered}= \frac{Sin^4A + Cos^4A}{Cos^2A . Sin^2A}\\\\Using\: a^2 + b^2 = (a+b)^2 - 2ab\\\\a = Cos^2A \: \& \:b = Sin^2A\\\\= \frac{(Sin^2A + Cos^2A)^2 - 2Sin^2A Cos^2A}{Cos^2A Sin^2A} \\\\Sin^2A + Cos^2A = 1\\\\= \frac{1 -2Sin^2A Cos^2A}{Cos^2A Sin^2A}\end{lgathered}
=
Cos
2
A.Sin
2
A
Sin
4
A+Cos
4
A
Usinga
2
+b
2
=(a+b)
2
−2ab
a=Cos
2
A&b=Sin
2
A
=
Cos
2
ASin
2
A
(Sin
2
A+Cos
2
A)
2
−2Sin
2
ACos
2
A
Sin
2
A+Cos
2
A=1
=
Cos
2
ASin
2
A
1−2Sin
2
ACos
2
A
\begin{lgathered}= \frac{1}{Cos^2A Sin^2A} - 2\\\\= RHS\end{lgathered}
=
Cos
2
ASin
2
A
1
−2
=RHS
LHS=RHS
She needs to read 20 more minutes.
10x4=40
60-40=20
Step-by-step explanation:
follow the above attachment.
hope this helps you.
Answer:
Step-by-step explanation:
In slope-intercept form, the equation of a line is given by 
, where 
is the slope of the line, 
is the y-intercept, and 
represent the coordinates of any point the line passes through.
Since we're given two points the line passes through, we can find the slope of the line using the slope formula 
:
Now we can plug in any point the line passes through to find the y-intercept:
Thus, the equation of this line is equal to .
