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andrew-mc [135]
3 years ago
7

7(2s-3). We need help with this problem

Mathematics
1 answer:
eimsori [14]3 years ago
5 0

Answer:

7s

Step-by-step explanation:

7(2s-3) start with the parenthesis 2s-3 2-3 is 1 so then add the s in the one which is 1s then 7 times 1 is 7 then add the s to is which is 7s

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a triangle has a height of 34 inches and an area of 391 square inches. Which equation can be used to find the base of the triang
tester [92]

Answer:

The area of a triangle is the space contained within its 3 sides. To find out the area of a triangle, we need to know the length of its three sides. The sides should be measured in feet (ft) for square footage calculations and if needed, converted to inches (in), yards (yd), centimetres (cm), millimetres (mm) and metres (m). The formula:

Square feet to square meters: multiply ft² by 0.092903 to get m²

Square yards to square feet: multiply yd² by 9 to get ft²

Square feet to square yards: multiply ft² by 0.11111 to get yd²

Square yards to square meters: multiply yd² by 0.8

Step-by-step explanation:

3 0
3 years ago
Select the correct answer from each drop-down menu. In the figure, line segment AB is parallel to line segment CD. The measure o
victus00 [196]
<h3>Answer:</h3>

∠C = 40°

∠D = 75°

<h3>Step-by-step explanation:</h3>

AB ║ CD, so AD and BC are transversals. The angle pairs (A, D) and (B, C) are "alternate interior angles", hence congruent.

∠C = ∠B = 40°

∠D = ∠A = 75°

3 0
3 years ago
Please help! whats 15 divided by 12
katrin2010 [14]

Answer:

1.25

Step-by-step explanation:

4 0
3 years ago
What are the solutions of the equation x^4 + 6x^2 + 5 = 0? Use u substitution to solve.
Radda [10]

Answer:

second option

Step-by-step explanation:

Given

x^{4} + 6x² + 5 = 0

let u = x², then

u² + 6u + 5 = 0 ← in standard form

(u + 1)(u + 5) = 0 ← in factored form

Equate each factor to zero and solve for u

u + 1 = 0 ⇒ u = - 1

u + 5 = 0 ⇒ u = - 5

Change u back into terms of x, that is

x² = - 1 ( take the square root of both sides )

x = ± \sqrt{-1} = ± i ( noting that \sqrt{-1} = i ), and

x² = - 5 ( take the square root of both sides )

x = ± \sqrt{-5} = ± \sqrt{5(-1)} = ± \sqrt{5} × \sqrt{-1} = ± i\sqrt{5}

Solutions are x = ± i and x = ± i\sqrt{5}

3 0
2 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!
vodomira [7]

12x^2-75=3(4x^2-25)=3(2^2x^2-5^2)=3((2x)^2-5^2)=3(2x+5)(2x-5)\\\\\text{Used:}\ a^2-b^2=(a+b)(a-b)\\\\Answer:\ 5

8 0
3 years ago
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