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adelina 88 [10]
3 years ago
9

8. Example 1 - Calculating Hourly Wages

Mathematics
1 answer:
Genrish500 [490]3 years ago
4 0

Answer:

279.00

Step-by-step explanation:

7.75x36

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Between what two integers is √95?
andrey2020 [161]

Answer:

Between 9 and 10.

Step-by-step explanation:

We know that √81 = 9 and that √100 = 10.

Since √95 is between √81 and √100, we know it will be between 9 and 10.

√95 = 9.74679

4 0
3 years ago
If you had an item that was $32 and the markup is 40% what would the cost be​
Serggg [28]

Answer:

44.8

Step-by-step explanation:

multiple 32 by 1.4

6 0
3 years ago
1 Kg = 2.2046 pounds what will be the answer in round to nearest tenth 4550 pounds = ______ kg
Harrizon [31]

Answer:

2063.9 kg

Step-by-step explanation:

Given,

<u>1 kg = 2.2046 pounds</u>

This can also be written as:

<u>1 pound = 1/2.2046 kg</u>

We have to calculate the value of 4550 pounds in kg up to nearest 10th

Thus,

4550 pounds= \frac{4550}{2.2046} kg

Solving the above equation, we get:

4550 pounds = 2063.8664 kg

Rounding the above result to nearest tenth as:

<u>4550 pounds = 2063.9 kg</u>

6 0
3 years ago
CALCULUS - Find the values of in the interval (0,2pi) where the tangent line to the graph of y = sinxcosx is
Rufina [12.5K]

Answer:

\{\frac{\pi}{4}, \frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\}

Step-by-step explanation:

We want to find the values between the interval (0, 2π) where the tangent line to the graph of y=sin(x)cos(x) is horizontal.

Since the tangent line is horizontal, this means that our derivative at those points are 0.

So, first, let's find the derivative of our function.

y=\sin(x)\cos(x)

Take the derivative of both sides with respect to x:

\frac{d}{dx}[y]=\frac{d}{dx}[\sin(x)\cos(x)]

We need to use the product rule:

(uv)'=u'v+uv'

So, differentiate:

y'=\frac{d}{dx}[\sin(x)]\cos(x)+\sin(x)\frac{d}{dx}[\cos(x)]

Evaluate:

y'=(\cos(x))(\cos(x))+\sin(x)(-\sin(x))

Simplify:

y'=\cos^2(x)-\sin^2(x)

Since our tangent line is horizontal, the slope is 0. So, substitute 0 for y':

0=\cos^2(x)-\sin^2(x)

Now, let's solve for x. First, we can use the difference of two squares to obtain:

0=(\cos(x)-\sin(x))(\cos(x)+\sin(x))

Zero Product Property:

0=\cos(x)-\sin(x)\text{ or } 0=\cos(x)+\sin(x)

Solve for each case.

Case 1:

0=\cos(x)-\sin(x)

Add sin(x) to both sides:

\cos(x)=\sin(x)

To solve this, we can use the unit circle.

Recall at what points cosine equals sine.

This only happens twice: at π/4 (45°) and at 5π/4 (225°).

At both of these points, both cosine and sine equals √2/2 and -√2/2.

And between the intervals 0 and 2π, these are the only two times that happens.

Case II:

We have:

0=\cos(x)+\sin(x)

Subtract sine from both sides:

\cos(x)=-\sin(x)

Again, we can use the unit circle. Recall when cosine is the opposite of sine.

Like the previous one, this also happens at the 45°. However, this times, it happens at 3π/4 and 7π/4.

At 3π/4, cosine is -√2/2, and sine is √2/2. If we divide by a negative, we will see that cos(x)=-sin(x).

At 7π/4, cosine is √2/2, and sine is -√2/2, thus making our equation true.

Therefore, our solution set is:

\{\frac{\pi}{4}, \frac{3\pi}{4},\frac{5\pi}{4},\frac{7\pi}{4}\}

And we're done!

Edit: Small Mistake :)

5 0
2 years ago
Apply Your Knowledge
vladimir2022 [97]

Answer:

$25

Step-by-step explanation:

We know,

Monthly interest = (Principal × Interest rate) ÷ 12

Given,

Loan principal = $3,000

Interest rate = 10% = 0.10

Therefore, monthly interest = ($3,000 × 0.10) ÷ 12

Monthly interest = $300 ÷ 12

Monthly interest = $25

Therefore, the principal amount to be paid per month is = $(96.80 - 25) = $71.80.

So, Jamison will pay $25 as interest for the 36-month $3,000 loan.

8 0
3 years ago
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